Glencoe Algebra 2 Student Edition C2014

1st Edition

ISBN: 9780076639908

Author: McGraw-Hill Glencoe

Publisher: MCG

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Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear re…

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

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Question

Chapter 0.5, Problem 4E

(a)

To determine

Check whether the events are mutually exclusive or not mutually exclusive. Also, find the probability.

(a)

Expert Solution

Answer to Problem 4E

The probability of freshmen or female is $1320$ .

Explanation of Solution

Given Information:

In French class, 10 freshmen, 8 sophomores, 2 juniors

Female students = 9 freshmen, 2 sophomores, 1 junior

Formula Used:

Two events are mutually exclusive, when they occur at same time.

Calculation:

Find the total members in French class.

Total members in French class $=10+8+2=20$

Consider the probability $P$ (freshmen or female).

The event is not mutually exclusive because there are 9 freshmen as female.

Now, find the probability of freshmen or female.

$P(freshmen or female)=P(freshmen)Total outcomes+P(female)Total outcomes−P(freshmen and female)Total outcomes=1020+1220−920=10+12−920=1320$

Hence, the probability of freshmen or female is $1320$ .

(b)

To determine

Check whether the events are mutually exclusive or not mutually exclusive. Also, find the probability.

(b)

Expert Solution

Answer to Problem 4E

The probability of sophomore or male is $12$ .

Explanation of Solution

Given Information:

In French class, 10 freshmen, 8 sophomores, 2 juniors

Female students = 9 freshmen, 2 sophomores, 1 junior

Formula Used:

Two events are mutually exclusive, when they occur at same time.

Calculation:

Find the total members in French class.

Total members in French class $=10+8+2=20$

Consider the probability $P$ (sophomoreor or male)

$Male sophomores=Total sophomores–Female sophomores=8−2=6$

The event is not mutually exclusive because there are 6 sophomores as male.

Now, find the probability of sophomore or male.

$P(sophomore or male)=P(sophomore)Total outcomes+P(male)Total outcomes−P(sophomore and male)Total outcomes=820+820−620=8+8−620=1020=12$

Hence, the probability of sophomore or male is $12$ .

(c)

To determine

Check whether the events are mutually exclusive or not mutually exclusive. Also, find the probability.

(c)

Expert Solution

Answer to Problem 4E

The probability of freshman or sophomore is $910$ .

Explanation of Solution

Given Information:

In French class, 10 freshmen, 8 sophomores, 2 juniors

Female students = 9 freshmen, 2 sophomores, 1 junior

Formula Used:

Two events are mutually exclusive, when they occur at same time.

Calculation:

Find the total members in French class.

Total members in French class $=10+8+2=20$

Consider the probability $P$ (freshman or sophomore).

The event is mutually exclusive because a student cannot be both freshman or sophomore.

Now, find the probability of freshman or sophomore.

$P(freshman or sophomore)=P(freshman)Total outcomes+P(sophomore)Total outcomes=1020+820=10+820=1820=910$

Hence, the probability of freshman or sophomore is $910$ .

Chapter 0.5, Problem 3E

Chapter 0.5, Problem 5E

Chapter 0 Solutions

Glencoe Algebra 2 Student Edition C2014

Ch. 0.1 - Prob. 1E Ch. 0.1 - Prob. 2E Ch. 0.1 - Prob. 3E Ch. 0.1 - Prob. 4E Ch. 0.1 - Prob. 5E Ch. 0.1 - Prob. 6E Ch. 0.1 - Prob. 7E Ch. 0.1 - Prob. 8E Ch. 0.1 - Prob. 9E Ch. 0.1 - Prob. 10E

Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.2 - Prob. 1E Ch. 0.2 - Prob. 2E Ch. 0.2 - Prob. 3E Ch. 0.2 - Prob. 4E Ch. 0.2 - Prob. 5E Ch. 0.2 - Prob. 6E Ch. 0.2 - Prob. 7E Ch. 0.2 - Prob. 8E Ch. 0.2 - Prob. 9E Ch. 0.2 - Prob. 10E Ch. 0.2 - Prob. 11E Ch. 0.2 - Prob. 12E Ch. 0.2 - Prob. 13E Ch. 0.2 - Prob. 14E Ch. 0.2 - Prob. 15E Ch. 0.2 - Prob. 16E Ch. 0.2 - Prob. 17E Ch. 0.2 - Prob. 18E Ch. 0.3 - Prob. 1E Ch. 0.3 - Prob. 2E Ch. 0.3 - Prob. 3E Ch. 0.3 - Prob. 4E Ch. 0.3 - Prob. 5E Ch. 0.3 - Prob. 6E Ch. 0.3 - Prob. 7E Ch. 0.3 - Prob. 8E Ch. 0.3 - Prob. 9E Ch. 0.3 - Prob. 10E Ch. 0.3 - Prob. 11E Ch. 0.3 - Prob. 12E Ch. 0.3 - Prob. 13E Ch. 0.3 - Prob. 14E Ch. 0.3 - Prob. 15E Ch. 0.3 - Prob. 16E Ch. 0.3 - Prob. 17E Ch. 0.3 - Prob. 18E Ch. 0.3 - Prob. 19E Ch. 0.3 - Prob. 20E Ch. 0.3 - Prob. 21E Ch. 0.3 - Prob. 22E Ch. 0.3 - Prob. 23E Ch. 0.3 - Prob. 24E Ch. 0.4 - Prob. 1E Ch. 0.4 - Prob. 2E Ch. 0.4 - Prob. 3E Ch. 0.4 - Prob. 4E Ch. 0.4 - Prob. 5E Ch. 0.4 - Prob. 6E Ch. 0.4 - Prob. 7E Ch. 0.4 - Prob. 8E Ch. 0.4 - Prob. 9E Ch. 0.4 - Prob. 10E Ch. 0.4 - Prob. 11E Ch. 0.4 - Prob. 12E Ch. 0.4 - Prob. 13E Ch. 0.4 - Prob. 14E Ch. 0.4 - Prob. 15E Ch. 0.4 - Prob. 16E Ch. 0.4 - Prob. 17E Ch. 0.4 - Prob. 18E Ch. 0.4 - Prob. 19E Ch. 0.5 - Prob. 1E Ch. 0.5 - Prob. 2E Ch. 0.5 - Prob. 3E Ch. 0.5 - Prob. 4E Ch. 0.5 - Prob. 5E Ch. 0.5 - Prob. 6E Ch. 0.5 - Prob. 7E Ch. 0.5 - Prob. 8E Ch. 0.5 - Prob. 9E Ch. 0.5 - Prob. 10E Ch. 0.6 - Prob. 1E Ch. 0.6 - Prob. 2E Ch. 0.6 - Prob. 3E Ch. 0.6 - Prob. 4E Ch. 0.6 - Prob. 5E Ch. 0.6 - Prob. 6E Ch. 0.6 - Prob. 7E Ch. 0.6 - Prob. 8E Ch. 0.6 - Prob. 9E Ch. 0.6 - Prob. 10E Ch. 0.6 - Prob. 11E Ch. 0.6 - Prob. 12E Ch. 0.6 - Prob. 13E Ch. 0.6 - Prob. 14E Ch. 0.6 - Prob. 15E Ch. 0.6 - Prob. 16E Ch. 0.6 - Prob. 17E Ch. 0.7 - Prob. 1E Ch. 0.7 - Prob. 2E Ch. 0.7 - Prob. 3E Ch. 0.7 - Prob. 4E Ch. 0.7 - Prob. 5E Ch. 0.7 - Prob. 6E Ch. 0.7 - Prob. 7E Ch. 0.7 - Prob. 8E Ch. 0.7 - Prob. 9E Ch. 0.7 - Prob. 10E Ch. 0.7 - Prob. 11E Ch. 0.7 - Prob. 12E Ch. 0.8 - Prob. 1E Ch. 0.8 - Prob. 2E Ch. 0.8 - Prob. 3E Ch. 0.8 - Prob. 4E Ch. 0.8 - Prob. 5E Ch. 0.8 - Prob. 6E Ch. 0.8 - Prob. 7E Ch. 0.8 - Prob. 8E Ch. 0.8 - Prob. 9E Ch. 0.8 - Prob. 10E Ch. 0.8 - Prob. 11E Ch. 0.8 - Prob. 12E Ch. 0.8 - Prob. 13E Ch. 0.8 - Prob. 14E Ch. 0.8 - Prob. 15E Ch. 0.8 - Prob. 16E Ch. 0.8 - Prob. 17E Ch. 0.8 - Prob. 18E Ch. 0.9 - Prob. 1E Ch. 0.9 - Prob. 2E Ch. 0.9 - Prob. 3E Ch. 0.9 - Prob. 4E Ch. 0.9 - Prob. 5E Ch. 0.9 - Prob. 6E Ch. 0.9 - Prob. 7E Ch. 0.9 - Prob. 8E Ch. 0.9 - Prob. 9E Ch. 0.9 - Prob. 10E Ch. 0.9 - Prob. 11E Ch. 0 - Prob. 1PR Ch. 0 - Prob. 2PR Ch. 0 - Prob. 3PR Ch. 0 - Prob. 4PR Ch. 0 - Prob. 5PR Ch. 0 - Prob. 6PR Ch. 0 - Prob. 7PR Ch. 0 - Prob. 8PR Ch. 0 - Prob. 9PR Ch. 0 - Prob. 10PR Ch. 0 - Prob. 11PR Ch. 0 - Prob. 12PR Ch. 0 - Prob. 13PR Ch. 0 - Prob. 14PR Ch. 0 - Prob. 15PR Ch. 0 - Prob. 16PR Ch. 0 - Prob. 17PR Ch. 0 - Prob. 18PR Ch. 0 - Prob. 19PR Ch. 0 - Prob. 20PR Ch. 0 - Prob. 21PR Ch. 0 - Prob. 22PR Ch. 0 - Prob. 23PR Ch. 0 - Prob. 24PR Ch. 0 - Prob. 25PR Ch. 0 - Prob. 26PR Ch. 0 - Prob. 27PR Ch. 0 - Prob. 28PR Ch. 0 - Prob. 29PR Ch. 0 - Prob. 30PR Ch. 0 - Prob. 1PO Ch. 0 - Prob. 2PO Ch. 0 - Prob. 3PO Ch. 0 - Prob. 4PO Ch. 0 - Prob. 5PO Ch. 0 - Prob. 6PO Ch. 0 - Prob. 7PO Ch. 0 - Prob. 8PO Ch. 0 - Prob. 9PO Ch. 0 - Prob. 10PO Ch. 0 - Prob. 11PO Ch. 0 - Prob. 12PO Ch. 0 - Prob. 13PO Ch. 0 - Prob. 14PO Ch. 0 - Prob. 15PO Ch. 0 - Prob. 16PO Ch. 0 - Prob. 17PO Ch. 0 - Prob. 18PO Ch. 0 - Prob. 19PO Ch. 0 - Prob. 20PO Ch. 0 - Prob. 21PO Ch. 0 - Prob. 22PO Ch. 0 - Prob. 23PO Ch. 0 - Prob. 24PO Ch. 0 - Prob. 25PO Ch. 0 - Prob. 26PO Ch. 0 - Prob. 27PO Ch. 0 - Prob. 28PO Ch. 0 - Prob. 29PO Ch. 0 - Prob. 30PO

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