Concept explainers
(a)
To add a column showing the experimental probability of landing on each given color with the next spin.
(a)
Explanation of Solution
Given Information:
The following is the table showing the results of various spins
Color | Frequency |
Red | |
Blue | |
Yellow | |
Orange | |
Purple | |
Green | |
Total |
The total number of spins is
The probability for any event
For the red color favorable cases are
Make the table again by calculating the probabilities as shown.
Color | Frequency | Probability |
Red | ||
Blue | ||
Yellow | ||
Orange | ||
Purple | ||
Green | ||
Total |
The table shows the probabilities for different color spinners.
(b)
Draw the bar diagram showing the experimental probabilities.
(b)
Explanation of Solution
GRAPH:
The following bar graph shows the experimental probabilities.
Take color on x - axis and probability on y - axis and draw the bar graph as shown below.
Bar graph for the experimental probabilities.
(c)
Draw a table by adding a column that showing the theoretical probability of the spinner.
(c)
Explanation of Solution
There are six colors and all colors have equal probabilities.
Since, the total probability is
The following table shows the theoretical probabilities in the table.
Color | Frequency | Probability |
Red | ||
Blue | ||
Yellow | ||
Orange | ||
Purple | ||
Green | ||
Total |
The table showing the theoretical probabilities.
(d)
Create a bar diagram showing the theoretical probabilities.
(d)
Explanation of Solution
GRAPH:
To plot the bar graph, proceed as follows.
Take color on x - axis and probability on y - axis and draw the bar graph as shown below.
Bar graph for the theoretical probabilities.
(e)
Interpret the graph by comparing the graphs created in above parts (b) and (d)
(e)
Explanation of Solution
In the first bar graph the experimental probabilities are given which is maximum for orange. Therefore, the probability of spinner landing on orange is more than green. So according the bar graph higher the length of bar, higher the probability of landing on that color.
But in the second bar graph all the bars have equal length implying that probability of landing on all the colors is same. All the colors have equal probability.
Chapter 0 Solutions
Glencoe Algebra 2 Student Edition C2014
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