You’re inside a metal building that blocks radio waves, but you’re trying to make a call with your cell phone, which broadcasts at a frequency of 950 MHz. Down the hall from you is a narrow win- dow measuring 35 cm wide. What's the horizontal angular width of the beam (i.e., the angle between the first minima) from your phone as it emerges from the window?
You’re inside a metal building that blocks radio waves, but you’re trying to make a call with your cell phone, which broadcasts at a frequency of 950 MHz. Down the hall from you is a narrow win- dow measuring 35 cm wide. What's the horizontal angular width of the beam (i.e., the angle between the first minima) from your phone as it emerges from the window?
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Question
Transcribed Image Text:You're inside a metal building that blocks radio waves, but you're
trying to make a call with your cell phone, which broadcasts at a
frequency of 950 MHz. Down the hall from you is a narrow win-
dow measuring 35 cm wide. What's the horizontal angular width
of the beam (i.e., the angle between the first minima) from your
phone as it emerges from the window?
Expert Solution
Concept and Principle:
- Waves are capable of bending around obstacles when the wavelength and the size of the obstacle are comparable. If the aperture is small enough even light is capable of diffraction.
- A single slit forms a diffraction pattern due to interference of the diffracted waves. But the pattern formed is different, it has a larger central maximum and the intensity reduces rapidly on either side.
- The condition for minima or destructive interference is given by,
Here d is the width of the slit, θ is the diffraction angle, m is the order of the fringe, and λ is the wavelength of the source.
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