you have found a recessive mutant fruit fly with no antennae. You interbreed this fly with its offspring and generate a true breeding mutant line of flies. A colleague later informs you that they have done the same thing. You borrow some of her antennaless flies, cross them to yours and in the F1 all of the flies are wild-type (have antennae). Which of the following is true? a) only one gene controls antennae development, and the parents of your cross each carry a different allele of that gene b) the two different antennaless alleles fail to complement each other c) each of the parents in your cross represents a mutation in a different gene that contributes to antennae development in flies d) without molecular data, it is impossible to determine whether one or two genes are controlling the development of this structure in flies

A new gene is being investigated in fruit flies. The recessive allele of this gene (b) causes the wings to develop a blue color, while the dominant allele (b+) permits wild-type colorless wings to develop. Preliminary studies indicate that this new gene is located on the X-chromosome. You decided to perform a two-point testcross to determine its positionrelative to the well-established garnet eyes gene (g). You cross a female heterozygous for both genes with a testcross male fly and obtain the male offspring results shown in table 1, below. Is the original female a coupling or repulsion heterozygote? What is the map distance between genes b and g?. Based on these results, gene b must be located between what two genes on the map? You perform another two-point testcross between gene b and gene v and obtained the results in table 2, below. Now, you can localize gene b to be specifically between which two genes?

In the rare rainbow rose, it has been shown that flower color is controlled by 2 genes. No one knows how the 2 genes are related and several hypotheses have emerged to explain how they interact to produce flowers with purple, yellow, and green pedals. You cross purple and green flowering plants, and find that F1 are all yellow colored. You allow F1 to self-fertilize and this produces 222 purple, 222 yellow and 222 green flowers. The 2 most popular theories are: a co-dominance relationship or an epistatic relationship between the 2 genes. Your team deduces that if co-dominance should result in 216 purple, 220 yellow and 230 green. Where as, an epistatic relationship should result in 250 purple, 200 yellow, and 216 green.   1-Which hypothesis is correct? a- Co-dominace  b- Epistatic  and The odds the theory  you selected is correct  is (less or greater) than (10%,25%,50%,90%)

My friend Pierre is red-green color blind and so is his father, but his mother is not color-blind. In the diagram below: a) Indicate the sex chromosomes of each member of Pierre's family b) Indicate the color-blindness allele associated with each chromosome of Pierre and his family (let B represent the color vision allele and let b represent a color blindness allele. If an allele cannot be determined with certainty, label the chromosome with a question mark c) Finally, determine the probability that Pierre's sister is color blind. Explain your reasoning.

In humans, the recessive allele that causes a form of red-green colour blindness (c) is found on the X chromosome. a.) Determine the genotypes and phenotypes of the F1 generation from a colour-blind father and a mother who is homozygous for normal colour vision. b.) Determine the genotypes and phenotypes of the F1 generation from a father who has normal colour vision and a mother who is heterozygous for colour vision. c.) Draw a Punnett square to determine the genotypes of parents that could produce a daughter who is colour-blind

Suppose researchers identified two Drosophila melanogaster mutant phenotypes. One phenotype is called maniac and the other is called shiny. In order to determine the mode of inheritance of the mutant allele responsible for each phenotype, males that have both mutant phenotypes are mated with wild-type (wt) females to produce F₁ progeny. Then, the F₁ progeny are mated together and the F2 progeny are scored. F₁ phenotypic class maniac male maniac female n 481 478 autosomal dominant for maniac and X-linked dominant for shiny autosomal recessive for maniac and autosomal recessive for shiny autosomal dominant for maniac and X-linked recessive for shiny X-linked dominant for maniac and X-linked recessive for shiny What is the genotype of the original male parent? F2 phenotypic class maniac female maniac male What is the mode of inheritance for the genes controlling maniac and shiny? maniac, shiny male shiny male wt female wt male homozygous mutant at both loci heterozygous mutant at one…

In a cross between a black and a white guinea pig, all members of the F₁ generation are black. The F2 generation is made up of approximately 3/4 black and 1/4 white guinea pigs. Let's call the gene associated with guinea pig color (A). What are the parent genotypes? A. (AA) and (AA) B. (AA) and (aa) C. (Aa) and (aa) D. (Aa) and (Aa) E. There is more than one correct answer What are the F1 genotypes? A. All (AA) B. All (Aa) C. ½ (Aa) and ½ (aa) D. 14 (AA), 1 (Aa), ¼ (aa) E. 1 (AA) and ½ (Aa)