Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the element. Ex: lowerScores = {5, 0, 2, -3} becomes {4, 0, 1, 0}. #include using namespace std; int main() {    const int SCORES_SIZE = 4;    int lowerScores[SCORES_SIZE];    int i;    for (i = 0; i < SCORES_SIZE; ++i) {       cin >> lowerScores[i];    }    /* Your solution goes here  */    for (i = 0; i < SCORES_SIZE; ++i) {       cout << lowerScores[i] << " ";    }    cout << endl;    return 0; }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the element. Ex: lowerScores = {5, 0, 2, -3} becomes {4, 0, 1, 0}.

#include <iostream>
using namespace std;

int main() {
   const int SCORES_SIZE = 4;
   int lowerScores[SCORES_SIZE];
   int i;

   for (i = 0; i < SCORES_SIZE; ++i) {
      cin >> lowerScores[i];
   }

   /* Your solution goes here  */

   for (i = 0; i < SCORES_SIZE; ++i) {
      cout << lowerScores[i] << " ";
   }
   cout << endl;

   return 0;
}

Expert Solution
Step 1

Algorithm:

for (initialExpression; testExpression; updateExpression){

            // body of the loop

}

Step 1: The initialExpression initializes and declares variables and executes only once.

Step 2: The condition is evaluated. If the condition is true, the body of the for loop executed.

Step 3: The update expression updates the value of initialExpression.

Step 4: The condition is evaluated again. The process continues until the condition is false.

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