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#include #include int findRepeat(char* s) { int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++) { for (j = i + 1; j < strlen(s); j++) { if (s[i] == s[j]) { p = i; break; } } if (p != -1) break; } return p; } int main() { char str[] = "Hello World"; int pos = findRepeat(str); if (pos == -1) printf("Not found"); else printf("%c", str[pos]); return 0; } can you please explain this code for me

#include #include int findRepeat(char* s) { int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++) { for (j = i + 1; j < strlen(s); j++) { if (s[i] == s[j]) { p = i; break; } } if (p != -1) break; } return p; } int main() { char str[] = "Hello World"; int pos = findRepeat(str); if (pos == -1) printf("Not found"); else printf("%c", str[pos]); return 0; } can you please explain this code for me

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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#include <stdio.h>
#include <string.h>

int findRepeat(char* s)
{
int p , i , j;

p = -1;

for (i = 0 ; i < strlen(s) ; i++)
{
for (j = i + 1; j < strlen(s); j++)
{
if (s[i] == s[j])
{
p = i;
break;
}
}
if (p != -1)
break;
}
return p;
}

int main()
{
char str[] = "Hello World";
int pos = findRepeat(str);
if (pos == -1)
printf("Not found");
else
printf("%c", str[pos]);
return 0;
}
can you please explain this code for me 

 

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