With a doubling time of 180 minutes and a starting population size of 10 cells, how many cells will be present after 72 hours, assuming no cell death?

Bacteria grown in a lab experience what is called an 'exponential phase' of population growth. Suppose that, during this phase, a colony of Escherichia coli you are growing has a per capita growth rate, r, of 0.0347 per minute. If the size of your colony at the start of the exponential phase is 0.25 billion cells, then approximately how large will it be in 120 minutes?

Answer choices: 1) a cell with two complete sets of chromosomes  2) a chromosome pair, one maternal and one paternal 3) the events that occur from the time a cell forms until the time it divides 4) time of cell growth 5) cell division that maintains chromosome number 6) a reproductive mode by which offspring are produced by one parent only 7) an exact copy of a chromosome

#7

Do any of the methods for “assisted reproduction” make you uncomfortable? Explain.

You need linear-linear paper and log-linear paper (also called semi-log paper), for linear-linear,10 squares per inch. For log-linear = semi-log you need at least 3 full cycles.   Plot the values below on each type of paper, then select two points marking an approximate doubling of cell density and interpolate back to the ‘x’ axis to determine the time. Indicate the bracketing for your estimate, and state ‘g= ____ hr’     Time (minutes)          OD420                   0                      0.091                          20                     0.092                                         40                    0.111                          60                     0.152                          80                     0.208          100                     0.303          120                     0.430          140                     0.577          160                     0.732         180                      0.902          200                     1.001          220…

Section 1- Question 14 The separation of cells and cellular components is accomplished with a centrifuge. A sample of cells is first blended to mechanically break apart some of the cells releasing their contents to form a cell homogenate. The remaining whole cells and cell components are separated based on their sedimentation rate by centrifuging the sample at increasingly high speed. The centrifuge spins at up to several thousand rotations per minute (rpm) forcing material to accumulate as a pellet at the bottom of the tube. The liquid portion is removed and centrifuged again to yield four (4) pellets containing the cells or cell components listed in the diagram. Cell homogenate Patient Patient 1 Patient 2 Patient 3 Low speed Patient 4 Medium speed .. High speed .. - ☐☐☐☐ Pellet 1 Whole cells Nuclei Cytoskeletons The separation of whole cells is required for the diagnosis and treatment of certain disease processes in humans. Four patients each exhibiting unique symptoms are shown in…