Why is there no output to this? It should be "6" as the output but there is nothing. Can someone help me with this in python? def foo(n):     if (len(n)==0):         return "even"     elif (len(n) == 1):         return "odd"     else:         return foo(n[0:(len(n-2))])      def main():     print(foo("George")) if __name__ == "main":     main()

JAVA Language:  Transpose Rotate.  Question:  Modify Transpose.encode() so that it uses a rotation instead of a reversal. That is, a word like “hello” should be encoded as “ohell” with a rotation of one character. (Hint: use a loop to append the letters into a new string)         import java.util.*;            public class TestTranspose {        public static void main(String[] args) {          String plain = "this is the secret message";   // Here's the message           Transpose transpose = new Transpose();          String secret = transpose.encrypt(plain);          System.out.println("\n ********* Transpose Cipher Encryption *********");          System.out.println("PlainText: " + plain);    // Display the results          System.out.println("Encrypted: " + secret);          System.out.println("Decrypted: " + transpose.decrypt(secret));// Decrypt        }      }            abstract class Cipher {        public String encrypt(String s) {          StringBuffer result = new…

def hailstone(n):  h.append(int(n))  if n == 1:    return h  while n != 1:    if n % 2 == 0:      return hailstone(int(n/2))    else:      return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0:    print("N must be positive!")else:    print("Hailstone sequences for 1 to " + str(y) + ": ")    m=0;    i=1    for x in range(1, y+1):         n = i        h = []        h = hailstone(n)        print(*h)        print(",")        s=len(h)        if s > m:            m=s            flag=n        i=i+1    print("First longest sequence found in n =", + flag )   How can I fix this code if I want a comma between each number, not each line?

In Java:  Forms often allow a user to enter an integer. Write a program that takes in a string representing an integer as input, and outputs yes if every character is a digit 0-9. Ex: If the input is: 1995 the output is: yes Ex: If the input is: 42,000 or 1995! the output is: no Hint: Use a loop and the Character.isDigit() function.

In PYTHON, what is the order of execution sequence for the following code? The digits at the beginning of each line of code only indicate the line numbers. 0:m = 0; n = 1 1: smaller -0 2:for p in range (n + 1) 3: smaller += p 4:if smaller > n: 5: smaller 6:print (smaller) a) 0, 1, 2, 3, 4, 5, 6. b) 0, 1, 2, 3, 4, 6. c) 0, 1, 2, 4, 6. d) 0, 1, 2, 3, 2, 3, 4, 6.

I have two questions: Is my programs code the most effective way at finding recursion or is there a much better and cleaner way? Why is the program showing 0 when I implement a number that depth is greater than 100? Shouldn't it show the number 1?   Source code: package recursiveModule; public class RecursiveMethod {    public static long calculateFactorial(int n, int depth) {        if (depth > 100 || n <= 1) {            return 1;        }                return n * calculateFactorial(n - 1, depth + 1);    }          public static void main(String[] args) {                             System.out.println("Factorial of 1 is " + RecursiveMethod.calculateFactorial(1, 0));                System.out.println("Factorial of 8 is " + RecursiveMethod.calculateFactorial(8, 0));                                      System.out.println("Factorial of 101 is " + RecursiveMethod.calculateFactorial(101, 0));                                   } }

Keeping data structures and algorithms in mind, can you help me to write these two functions in java? The factorial of a positive integer n —which we denote as n!—is the product of n and the factorial of n − 1. The factorial of 0 is 1. Write two different recursive methods that each return the factorial of n. Include the two methods in a file called Test.java   What to submit: The Test.java

JAVA: Which is/are correct statement(s) about the Recursion? (Select all that apply) We can use for loop and while loop in recursion. We solve a problem that depends on solving smaller occurrences of the same problem. We have high performance while using recursion rather than iteration. We have high performance while using iteration rather than recursion. Easy to implement the algorithm while using recursion but hard to find the time complexity. Easy to implement the algorithm while using iteration but hard to find the time complexity. Base case is a simple occurrence that cannot be answered directly. Recursive case is a more complex occurrence of the problem that cannot be directly answered, but can instead be described in terms of smaller occurrences of the same problem. We must have exact one base case and one recursive case. We must have at least one base case. We must have at least one recursive case.