Which of the following statements print set contains all items from setl or set2 not both from the given sets? setl = set(["a", "b", "c") set2 = set(["a", "e"]) %3D %3D Select one: O a print(set1I set2) O b. print(set1 & set2) O c. print(set1 ^ set2) O d. print(set1 - set2)
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- Ior ch in inputStr : What would this code display? nameList = ["John", "Harry", "Jesse", "John", "Harry", "Harry"] if "Raheem" in nameList: print("Name found! ") Select one: Oa. Nothing O b. "Name found!" O c. "Raheem" O d. An error CLEAR MY CHOICE e here to search F2 F3 F4 F5 F6 F7 PA 23Create a spyder(anaconda) program that will ask the user to enter 2 non-empty set and display their intersection and union. Design the following function in the program: set_intersection-this function gets the intersection of 2 given sets set_union-this function gets the union of two given setsSets store their elements in an unordered fashion.True or False
- the row vector can also be created ?using the and operator O bracket operator O colon operator O hash operator OINT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].Set are ordered but not indexed True or false.
- Search if Ram is exist : if exiset print the value; else : student does not exist . <?php $marks = array( "Sara" => array( "Programming" => 95, "DataBase" => 85, "Web" => 74, ), "Diana" => array( "Programming" => 78, "DataBase" => 98, "Web" => 66, ), "Amy" => array( "Programming" => 88, "DataBase" => 76, "Web" => 99, ), ); ?>Show the output of the following code:set1 = {1, 2, 3}set2 = {3, 4, 5}set3 = set1 | set2 print(set1, set2, set3)set3 = set1 – set2print(set1, set2, set3)set3 = set1 & set2print(set1, set2, set3)set3 = set1 ^ set2print(set1, set2, set3)The elements in the set cannot be accessed using indexing and slicing, choose whether this statement is true or false. a. True b. False Clear my choice
- GIven the statement below: intA=(3,6,9}, A.length can't be used to display the number of elements in the array True FalseDec2Hex function : def decimal_to_hex(number): hex_map = {0: '0', 1: '1', 2: '2', 3: '3', 4: '4', 5: '5', 6: '6', 7: '7', 8: '8', 9: '9', 10: 'A', 11: 'B', 12: 'C', 13: 'D', 14: 'E', 15: 'F'} hex_digits = [] while number > 0: hex_digits.append(hex_map[number % 16]) number //= 16 # Reverse the order of the hex digits and join them to form the final hex string hex_string = ''.join(reversed(hex_digits)) return f'0x{hex_string}' if hex_string else '0x0' Perform a Profile of your Dec2Hex function. Write a function that takes a timedate object as a parameter andcalculates the number of years from NOW to the time in the timedateobject. Add unit-testing code to your Dec2Hex exercise, and then perform aUnit test of the updated Dec2Hex code.Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.