eturns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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INT_MIN = -32767

def cut_rod(price):
    """
    Returns the best obtainable price for a rod of length n and
    price[] as prices of different pieces
    """
    n = len(price)
    val = [0]*(n+1)

    # Build the table val[] in bottom up manner and return
    # the last entry from the table
    for i in range(1, n+1):
        max_val = INT_MIN
        for j in range(i):
            max_val = max(max_val, price[j] + val[i-j-1])
        val[i] = max_val

    return val[n]

# Driver program to test above functions
arr = [1, 5, 8, 9, 10, 17, 17, 20].

 

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