Which of the following are elongation factors involved in the release of free tRNAs? a.EF-G b.EF-Ts c.EF-Tu d.EF-P
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Which of the following are elongation factors involved in the release of free tRNAs?
a.EF-G
b.EF-Ts
c.EF-Tu
d.EF-P
Step by step
Solved in 2 steps
- Given the following mRNA and amino acids, construct a polypeptide from this tRNA strand. tRNA UAA CCA UUA UAA mRNA Amino Acids AUU = isoleucine AAU = asparginine GGU = glycine GUC = valine GAG = glutamic acidThe following is a portion of a protein: met-trp-tyr-arg-gly-pro-thr-Various mutant forms of this protein have been recovered. Using the normal and mutant sequences, determine the DNA and mRNA sequences that code for this portion of the protein, and explain each of the mutations. a. met-trp- b. met-cys-ile-val-val-leu-gln- c. met-trp-tyr-arg-ser-pro-thr- d. met-trp-tyr-arg-gly-ala-val-ile-ser-pro-thr-If a nonsense mutation can be suppressed by a tRNA mutation that changes an anticodon so that a nonsense codon can be translated, describe a mechanism for suppression of a frameshift mutation.
- The figure shows the position of two of these mutations a and b. The nucleotides are altered in these 2 different swo-1 mutant alleles. Use the genetic table to describe any AA changes.Name the type of mutation and describe its effect on swo-1 mRNA and protein for each of the mutations. 3. The swo-1 a mutation (insertion between C and G). 4. The swo-1 b mutation (C-to-T mutation for indicated C). 5. The swo-1 a mutation leads to worms with more body wall muscle, whereas worms with the swo-1 b mutation are not able to move. Based on these phenotypes and the findings from questions 3 and 4, describe the role thewild-type version of this protein plays in muscle function.Hydrogen bonds are important in DNA replication and transcription. They are relatively weak chemical bonds. Why is this a desirable feature for DNA? Describe the effect (s) of changing (mutating) the promoter on the transcription of the DNA strand/gene the promoter controls. What happens to protein synthesis if a nonsense codon is inserted into the gene? Explain why a point mutation does not necessarily change the original amino acid sequence. (Explain silent mutations) Choose any pentapeptide composed of five different amino acids. List the amino acids. Present one messenger RNA codon for each amino acids and the sequence of nucleotides on the DNA that originally coded for your pentapeptide.A substitution mutation that results in the formation of a stop codon and premature termination of the protein is called?
- An anticodon has the sequence GCG. What amino acid does this tRNA carry? What would be the effect of a mutation that changed the C of the anticodon to G?What potential polypeptides can be produced from the following mRNA sequence? There are more than one answer.. 5’ ...GGAGCUCGUUGUAUU... 3’ a. ser-ser-leu-tyr b. leu-cys-cys-ser-arg c. gly-ala-ser-trp-ile d. gly-ala-arg-cys-ile e. glu-leu-val-val f. You can't translate without a start codon. I know (d) is one of the answer but I'm stuck on how to find the rest. Please help.Determine whether this statement is true or false: Aminoacyl-tRNA synthetase covalently links the amino acid to the 5’ end of the correct tRNA molecule.
- A reversion is a mutation that returns a mutant codon back to acodon that gives a wild-type phenotype. At the DNA level, this typeof mutation can be an exact reversion or an equivalent reversion. An equivalent reversion produces a protein that is equivalent to thewild-type protein in structure and function. This outcome canoccur in two ways. In some cases, the reversion produces thewild-type amino acid (in this case, glutamic acid), but it uses adifferent codon than the wild-type gene. Alternatively, an equivalentreversion may substitute an amino acid structurally similarto the wild-type amino acid. In our example, an equivalent reversionhas changed valine to an aspartic acid. Because aspartic andglutamic acids are structurally similar—they are acidic aminoacids—this type of reversion can restore wild-type structure andfunction.Here is the question: The template strand within the codingsequence of a gene has the following sequence:3′–TACCCCTTCGACCCCGGA–5′This template produces the…For each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the amino acid sequence that have been left blank. If several sequences might work, choose only one. Furthermore, circle the start and the stop codons of each mRNA sequence. 1. DNA (3'-5') ACG TAC GGC CGG TTA AAG CAT ACT TTC TTG MRNA TRNA Amino Acid 2. DNA (3'-5') MRNA AUG ACU AGC UGG GGG UAU UAC UUU UAG AAA TRNA Amino Acid 3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Activate Go to Sett Amino AcidThe template strand of a segment of double-helical DNA contains the sequence – 5’-CTT-AAC-ACC-CCT-GAC-TTC-GCG-CCG-CAT-3’ a. What is the base sequence of the complementary strand of DNA? Indicate the 5’ and the 3’ ends. b. What is the base sequence of the mRNA that can be transcribed from this template DNA strand? Indicate the 5’ and the 3’ ends. c. What amino acid sequence can be coded by the mRNA in (b) starting from the 5’ end (or the N terminal amino acid)?