Which of the following affect the WIDTH of a confidence interval? (SELECT ALL THAT APPLY) Confidence level Sample size Sample Mean Standard deviation of the sample/population

Sample size 42, mean. 53.1, and standard deviation 8.2  An 80% confidence interval for population mean is

Question Help v The data below shows the sugar content in grams of several brands of children's and adults' cereals. Create and interpret a 95% confidence interval for the difference in the mean sugar content, uC-HA. Be sure to check the necessary assumptions and conditions. (Note: Do not assume that the variances of the two data sets are equal.) Full data set Children's cereal: 43.3, 56.1, 49.6, 42.2, 54, 47.6, 54.1, 42.9, 42.2, 43, 48.7, 40.4, 37.5, 57.6, 49.4, 50.5, 38.3, 57.1, 40.6, 32 Adults' cereal: 21.5, 28.5, 0.1, 6.1, 4.2, 24.8, 15.4, 12.5, 20.9, 8.3, 7.5, 11.2, 15.9, 11.5, 0.1, 16.9, 0.7, 0.2, 1.5, 6.4, 13.8, The confidence interval is ). (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. 1 1 part remaining Clear All

Rock band The Rolling Stones have played scores of concerts in the last twenty years. For 30 randomly selected Rolling Stones concerts, the mean gross earnings is 2.89 million dollars. Part a) Assuming a population standard deviation gross earnings of 0.5 million dollars, obtain a 99% confidence interval for the mean gross earnings of all Rolling Stones concerts (in millions). Confidence interval: ( Part b) Which of the following is the correct interpretation for your answer in part (a)? U A. We can be 99% confident that the mean gross earnings for this sample of 30 Rolling Stones concerts lies in the interval O B. There is a 99% chance that the mean gross earnings of all Rolling Stones concerts lies in the interval O c. If we repeat the study many times, 99% of the calculated confidence intervals will contain the mean gross earning of all Rolling Stones concerts. O D. None of the above