Using a t-table or a t-score calculator, find the value of t for sample size (n) of 25 to estimate 95% confidence interval for the population mean.

Use the margin of error of 5, confidence level of 98%, and o=30, find the minimum sample size required to estimate a normal distribution population mean µ.

You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)

The mean test score for a simple random sample of n=100 students was =80. The population standard deviation of test scores is σ=15. Construct a 95% confidence interval for the population mean test score μ.

The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14).  State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why?     22.95 is in the center of the interval. The means are definitely not different.     22.95 is just outside the 95% confidence interval. Can't say the means are really different.     22.95 is not equal to 20.7. The means are definitely different.     20.7 is just outside the 95% confidence interval. Can't say the means are really different.

If you want to construct a 90% confident interval for a population mean such that it is within a quarter (population) standard deviation from the sample mean, then what is the minimum sample size required?

Apply the t-interval procedure to find a 95% confidence interval for the mean arterial blood pressure of 8 children sampled if x=85.99 mm Hg and s=8.08 mm Hg

Using the t-table, find the critical value for a left-tailed test with a significance level of 10% and a sample size of 25.

Determine the margin of error in estimating the population mean, μ. Based on a sample of size 44, a 95% confidence interval for the mean score of all students, μ, on an aptitude test is from 67 to 72. Find the margin of error.

The accompanying data represent the running times of files produced by two motion-picture companies. Assume that the running-time differences are approximately normally distributed. Construct a 90% confidence interval for 90% confidence interval for μ - μ were created, should it be assumed that o² = = If a Company | 106 96 105 Time (minutes) 91 99 II 101 78 123 89 171 89 120 Click here to view page 1 of the table of critical values of the F-distribution, for alpha = 0.05. Click here to view page 2 of the table of critical values of the F-distribution, for alpha = 0.05. The confidence interval is < (Round to three decimal places as needed.)