What type of linkage is shown here? CH₂OH H K ОН H ОН H O Alpha (1,4) O Beta (1,2) Beta (1,6) O Alpha (1,2) O Alpha (1,6) ان O Beta (1,4) ОН H CH₂OH H ОН ОН H H CH2OH
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- C6H8 + O2 ------à CO2 + H2O How many grams of C6H8 are needed to from 72grams of H2O ?Hemoglobin is considered to be a tetrameric complex with a 64 kDa (α β)2. When attempting to purify hemoglobin, we must first purify the α and β monomers (about 16 kDa each) to prepare the tetramer. This is formed from the dimer intermediate: 2 α + 2 β -> 2 αβ -> (α β)2. The graph given represents a size-exclusion chromatogram after the refolding of the hemoglobin tetramer Using the size-exclusion chromatogram given, 1. Draw an SDS-Page Gel with a reducing agent such as BME using the three peaks listed on the graph.Titration of alanine by a strong base, for example NaOH, reveals two pk's. Which is the titration reaction occurring at pK1 (pK1 = %3D 2.34)? O-NH2 + COH →-NH + H2O O-COOH + OH →-CO + H20 -COOH + -NH2 → -COO" + -NH2+ -CoO +-NH2* → -COOH +-NH2 O -NH3* + OH →-NH2 + H2O
- Acid phosphatases are an important group of enzymes that can be detected in human blood serum. Under slightly acidic conditions (pH 5.0), this group of enzymes can hydrolyze biological phosphate esters as follows; R-O-P-O3-2+ H 20 OR-OH + HO-P-O3-2. Acid phosphatases are produced and can be detected in erythrocytes, kidney, spleen, the liver, and prostate gland. The enzyme from the prostate gland is clinically important because an increased activity in the blood is frequently an indication of cancer of the prostate gland. Tartrate ion can strongly inhibit the phosphatase from the prostate gland, but not acid phosphatases from other tissues. How can you use the information above to develop a specific procedure for measuring the activity of the acid phosphatase of the prostate gland in human blood serum?Name the types of glycosidic bonds found in this olygomer, from left to right (from 1 to 3) CH 20H CH 2OH CH 2OH но OH OH OH OH OH OH O alpha1-1, alpha1-4, n O alpha1-4, alpha1-4, n O alpha1-4, beta1-2 O alpha1-4, beta1-4 O beta1-4, alpha 1-4 « Previous Next Not saved Submit QuizPlease provide the name of the 12-lead
- why is CH3-CH-CH2-CH2-CH3 non imposable ? I OHYou have an aqueous solution of hemoglobin (pl = 6.8) at pH 5.2, and currently the proteins are soluble. If you had 1M HCl and 1M NaOH at your disposal, what could you do to precipitate the albumin out of solution? add NaOH to the solution O add HCl to the solution O add NaOH to the solution, then add equal volume of HCl to the solution O add HCl to the solution, then add equal volume of NaOH to the solutionHemoglobin is considered to be a tetrameric complex with a 64 kDa (α β)2. When attempting to purify hemoglobin, we must first purify the α and β monomers (about 16 kDa each) to prepare the tetramer. This is formed from the dimer intermediate: 2 α + 2 β -> 2 αβ -> (α β)2. 1. The graph given represents a size-exclusion chromatogram after the refolding of the hemoglobin tetramer. This process is not 100% efficient, so we may have leftovers of dimers and monomers. In the graph given, can we label the peaks given as a tetramer, dimer, or monomer?
- Which of the equations below best represents how excess acid in the blood plasma can be removed in the lungs by breathing? H+ (aq) + 0. 2(g) OH + H₂ CO (aq) OH+ + O (aq) 2(g) → H, CO. H + O₂ (aq) 2(g) 3(aq) 3(aq) → H₂O(g) + CO2(g) + CO2(g) → H₂O H, CO3(aq) → HCO, OH t + HCO3(aq) → H₂ CO3(g) → H₂O(g) (aq) → H, CO3(aq) 3 (aq) + CO2(g) H₂O(g) + CO2(g)The Hb Yakima variation is caused by the mutation D99H, which results in a shift in oxygen binding as shown in the graph. What effect does the D99H variation have on the [T] / [R] ratio of Hb Yakima protein conformation compared to Hb Normal and how does D99H alter oxygen affinity? Fractional saturation 1.0 2 Hb Yakima 20 Hb Normal 40 60 po, (kPa) 80 100You have an aqueous solution of hemoglobin (pl = 6.8) at pH 6.5, and currently the proteins are soluble. If you had 1 M HCl and 1M NaOH at your disposal, what could you do to precipitate the albumin out of solution? O add NaOH to the solution add HCl to the solution add NaOH to the solution, then add equal volume of HCl to the solution O add HCl to the solution, then add equal volume of NaOH to the solution An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Submit Answer Try Another Version 1 item attempt remaining