What is the infiltration capacity at 3 hours of a soil
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- 12. (Horton's equation for infiltration rate, ). One can use Horton's equation to estimate the infiltration rate of water into soil if the rainfall rate exceeds the infiltration rate. The Horton's equation states that: f = fe+ (fo-fc) x e-kt where f is the infiltration rate (cm h:¹), fe is the equilibrium infiltration rate (cm h 1), fo is the initial infiltration rate (cm h:¹), k is an empirical constant (h:¹), and t is time (h). Horton's equation can be integrated to yield an equation that represents the total volume of water that would infiltrate over a given period: V=A₁ [Fxα= 4, 16+ V = A₁ [fx dt = A₁ [lfc + (fo-fc) × e-k¹] x dt = A₂ × [fet + fo=fc (1 - e-*)] 0 where As is the unit area (1 m²) and V is the volume (m³). Sothan loamy sand has the following characteristics: fe= 6.68 cm h¹, fo = 8.81 cm h¹, k = 1.40 h ¹. Assuming the rate of precipitation exceeds the rate of infiltration throughout the storm event. 12.1. Find the infiltration rate at times of 12, 30, 60, and 120 min.…Solve the infiltration loss at t = 15 min in the exponential function boundary. Given data:fo = 300mm/hrfc = 60mm/hrassume k = 4.8/hrQuestion 2: After conduct an experiment, you found that the soil for the watershed have an initial rate of infiltration equal to 1.35 in./hr and a final capacity of 0.3 in./hr. Assuming that the time constant k = 0.4, calculate the soil infiltration capacity at the times 10 min, 15 min, 30 min, 1 hr, 2 hr, 4 hr, and 6 hr using Horton's equation. Infiltration
- The initial infiltration capacity of the soil is 0.0386cm per min. the time constant as 10.18 per min and the final capacity of soil for infiltration is 0.0683 cm per hour. Use Hortons equation to solve for ft in mm per hour at 3 min3. The Horton infiltration equation f(t) describes how the infiltration capacity (mm/hr) for the soil is changing with time as the soil becomes wetter. The accumulated infiltrated water (in mm) can be calculated using the integral of f(t), i.e., F(t). where, fo = initial infiltration capacity of dry soil (mm/hr) fc = final infiltration capacity when the soil has become saturated soil (mm/hr) k = time constant (hr4) Note that the Horton equation is only valid for ponding conditions. In a specific soil, the following parameters are known: fo = 35 (mm/hr) fc = 6 (mm/hr) k = 2 (hr 1) %3D What is the infiltration capacity after 15,30, and 60 min? How much water has infiltrated after 15, 30, and 60 min?An unconfined aquifer is 100 feet thick was evaluated using a field pumping test. The depth to groundwater is 10 feet. At a distance of 1000 feet, the drawdown was 40 feet, and at a distance of 5000 feet it was 20 feet. Find the permeability of the aquifer assuming that a steady-state of 960 gal/minute during the test in ft/sec.
- SITUATION 4 The soil under a dam has three layers with different coeffident of permeability. Determine the following: (a) Calculate the equivalent hydraulic conductivity in am/sec. (b) Compute the Transmissibility of the soil when the water table is at the ground surface, in sq.cm/ sec (Note: Transmissibility= k x distance) (c) Determine the seepage velocity of water moving through soil if it has a void ratio of 0.60 and a hydraulic gradient of 0.0018 in cm/hr. Illustration for Situation 4 KI = 0.000 I0 cm/sec at 3m K2= 0.032 cm/sec at 4m K3= 0.000041 cm/sec at GmGiven an initial rate of infiltration equal to 1.5 in./hr and a final capacity of 0.5 in./hr, use Horton’s equation tofind the infiltration capacity at the following times: t = 10 min, 15 min, 30 min, 1 hr, 2 hr, 4 hr, and 6 hr. Use atime constant ? = 0.25/ℎ�Estimate the capillary soil suction using the Green-Ampt equation if it takes 3.5 hours for an infiltration wetting front to travel 40 cm below the ground. The effective porosity of the soil (n) is 0.2 while its hydraulic conductivity is 2.5 cm/hour.
- The infiltration capacity in basin is represented by Horton's equation as fp=5.0 + e-St where fp is in cm/h and t is in hours. Assuming the infiltration to take place at capacity rates in a storm of 100 minutes duration, estimate the depth of infiltration in 1. the first two hour of the storm I 2. the second two hour of the stormHome workl: for a soil, F.C = 28% by dry weight, wp = 18% by volume, Allowable depletion (AD) = 50%, AS= 1.35, find: 1- readily available water by weight 2- Readily available water by volume. Home work2: from test data of infiltration experiment, D= 2.5 cm @t= 15 minute and D = 8 cm @t= 100 minute, determine: 1- base infiltration rate 2- time required to accumulate 15 cm depth 3- infiltration rate estimated by (mm/hour) at time =3 hours Home work3: A soil has d = 4.5(t) (mm/min) was irrigated by a basin. The moisture content before irrigation was 20 % by volume. The field capacity (F.C) was (22 %) by weight, the effective root zone is (1.2 m) and (AS=1.5), find the time required to complete the irrigation.The inital rate of infiltration of a watershed is estimated as 2.1 in/hr, the final capacity is 0.2 in/hr, and the time constant k, is 0.4 hr-1. Use Horton's Equation to find: A. The infiltration capacity is at t= 2.1 hr and t =6 hr; and B. The total volume of infiltration over the 6-hr period.