The initial infiltration capacity of the soil is 0.0386cm per min. the time constant as 10.18 per min and the final capacity of soil for infiltration is 0.0683 cm per hour. Use Hortons equation to solve for ft in mm per hour at 3 min
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- The infiltration capacity of a soil follows the Horton's exponential model f = C₁ + C₂ e-kt. During an experiment, the intial infiltration capacity was observed to be 200 mm/hr. After a long time the infiltration capacity was reduced to 25 mm/h. If the infiltration capacity after 1 hour was 90 mm/ h the value of the decay rate constant k (in h-¹, up to two decimal places) isResults of an infiltrometer test on a soil are given below. Determine the Horton's infiltration capacity equation for this soil by identifying the parameters fo, fc and k. Time from start (hr) 0.25 0.50 0.75 1.00 1.25 1.50 1.75 2.0 Infiltration capacity in cm/hr 5.6 3.20 2.10 1.50 1.20 1.10 1.0 1.0 96In Horton's infiltration equation fitted to data from a soil, the initial infiltration capacity is 10 mm/h, final infiltration capacity is 5 mm/h and the exponential decay constant is 0.5 h-1. Assuming the infiltration takes place at capacity rates, the total infiltration depth for a uniform storm of duration 8 hours is A 40 mm 60 mm 80 mm D 90 mm
- In Horton's infiltration equation fitted to data from a soil, the initial infiltration capacity is 10 mm/h, final infiltration capacity is 5 mm/h and the exponential decay constant is 0.5 h. Assuming the infiltration takes place at capacity rates, the total infiltration depth for a uniform storm of duration 8 hours is A 80 mm B 60 mm 40 mm 90 mmmassfall The infiltration capacity of soil in a small watershed was found to be 6 cm/h before a rainfall event. It was found to be 1.2 cm/h at the end of 8 hours of storm. If the total infiltration during the 8 hours period of storm was 15 cm, estimate the value of the decay coefficient K, in Horton's infiltration capacity equation.Home workl: for a soil, F.C = 28% by dry weight, wp = 18% by volume, Allowable depletion (AD) = 50%, AS= 1.35, find: 1- readily available water by weight 2- Readily available water by volume. Home work2: from test data of infiltration experiment, D= 2.5 cm @t= 15 minute and D = 8 cm @t= 100 minute, determine: 1- base infiltration rate 2- time required to accumulate 15 cm depth 3- infiltration rate estimated by (mm/hour) at time =3 hours Home work3: A soil has d = 4.5(t) (mm/min) was irrigated by a basin. The moisture content before irrigation was 20 % by volume. The field capacity (F.C) was (22 %) by weight, the effective root zone is (1.2 m) and (AS=1.5), find the time required to complete the irrigation.
- A 15 cm vertical soil sample is taken and placed in constant head permeameter. The surface area of the soil sample is 20 cm2. h1 is measured at 25 cm and h2 is 10 cm. The water that flows through the soil sample has a constant discharge and 95 cm3 is collected in 15 minutes. Calculate the hydraulic conductivity of the soil sample. What kind of soil you think this is?Problem (1) Based on the following figure, find the flow rate in m / sec/ m through the permeable soil layer. H = 4m H, = 2m h = 3.1m h L= 30m a =14° Impervious layer ст k = 0.05 sec Direction of flow Impervious layer12. (Horton's equation for infiltration rate, ). One can use Horton's equation to estimate the infiltration rate of water into soil if the rainfall rate exceeds the infiltration rate. The Horton's equation states that: f = fe+ (fo-fc) x e-kt where f is the infiltration rate (cm h:¹), fe is the equilibrium infiltration rate (cm h 1), fo is the initial infiltration rate (cm h:¹), k is an empirical constant (h:¹), and t is time (h). Horton's equation can be integrated to yield an equation that represents the total volume of water that would infiltrate over a given period: V=A₁ [Fxα= 4, 16+ V = A₁ [fx dt = A₁ [lfc + (fo-fc) × e-k¹] x dt = A₂ × [fet + fo=fc (1 - e-*)] 0 where As is the unit area (1 m²) and V is the volume (m³). Sothan loamy sand has the following characteristics: fe= 6.68 cm h¹, fo = 8.81 cm h¹, k = 1.40 h ¹. Assuming the rate of precipitation exceeds the rate of infiltration throughout the storm event. 12.1. Find the infiltration rate at times of 12, 30, 60, and 120 min.…
- Question 2: After conduct an experiment, you found that the soil for the watershed have an initial rate of infiltration equal to 1.35 in./hr and a final capacity of 0.3 in./hr. Assuming that the time constant k = 0.4, calculate the soil infiltration capacity at the times 10 min, 15 min, 30 min, 1 hr, 2 hr, 4 hr, and 6 hr using Horton's equation. InfiltrationSituation 1 – Refer to the picture. 1. Assume 3K1=K2=1.5K3=2K4 K1=3.5x10-2 (cm/s) Calculate the equivalent coefficient of permeability. 2. Assume 3K1=K2=1.5K3=2K4 K1=3.5x10-2 (cm/s) Calculate the rate of seepage 3. Assume 3K1=K2=1.5K3=2K4 K1=3.5x10-2 (cm/s) Calculate the height of water above C if piezometer was placed at that pointA catchment soil has a Horton infiltration parameter: f0=240 mm/hr, fc=30 mm/hr and k=0.2 min^-1. Calculate the infiltration rate right after two hours. Assuming a rain of constant intensity of 50 mm/hr occurs and lasts fo 3 hours, calculate the amount of rain that infiltrates into the soil.