Home workl: for a soil, F.C = 28% by dry weight, wp = 18% by volume,Allowable depletion (AD) = 50%, AS= 1.35, find: 1- readily available water byweight 2- Readily available water by volume.Home work2: from test data of infiltration experiment, D= 2.5 cm @t= 15minute and D = 8 cm @t= 100 minute, determine: 1- base infiltration rate 2- timerequired to accumulate 15 cm depth 3- infiltration rate estimated by (mm/hour) attime =3 hoursHome work3: A soil has d = 4.5(t) (mm/min) was irrigated by a basin. Themoisture content before irrigation was 20 % by volume. The field capacity (F.C)was (22 %) by weight, the effective root zone is (1.2 m) and (AS=1.5), find thetime required to complete the irrigation.

Solution; According to our guidelines we only give answer one at a time so please submit your…

Answered: Home workl: for a soil, F.C= 28% by dry…

Home workl: for a soil, F.C= 28% by dry weight, wp = 18% by volume, Allowable depletion (AD)- 50%, AS- 1.35, find: 1- readily available water by weight 2- Readily available water by volume.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter7: Permeability

Section: Chapter Questions

Problem 7.22P: Refer to Figure 7.24. The following data were collected during the field permeability measurement of...

See similar textbooks

Related questions

Q: A compacted soil weighs 131.1 pcf with recorded moisture content of 15%. What is the (a) saturated…

A: Given data: Weight of the soil sample (W) = 131.1 pcf water content (w) = 15% = 0.15 specific…

Q: Another unit for soil water potential is an atmosphere, which is very close to a bar (1 atm = 1.01…

Q: Earth is required to be excavated from the borrow pits for building embankment as shown in the…

Q: 3. If Liquidity Index (LI)0 <LI <1, the behavior of the soil is... A. dried C. liquid B. plastic D.…

A: 1)If Liquidity Index (LI)<0 ---> then, Soil is in "Semi-Plastic State or dry(Solid) State." 2)…

Q: Compaction test in the laboratory gave maximum dry unit weight of 18.15 kN/m3 at optimum moisture…

Q: GEOTECHNICAL ENGINEERING: The Liquid limit, plastic limit and the natural water content of the…

A: Given Data Liquid limit is 38% Plastic limit is 21% Natural water content is 30%

Q: 2. The soil layers below have a cross section of 100 mm x 100 mm each. The permeability of each soil…

Q: A3 If a soil has ESP= 50 and EC = 4.0 dS/m, what would be SAR (sodium adsorption ratio) and total…

A: Given data- Exchangeable sodium percentage (ESP) = 50 EC = 4.0 dS/m Gapon's Constant (KG) = 0.015

Q: 4.1.1 Borrow soil is used to fill a 75,000m3 depression. The borrow soil has the following…

A: Given:The volume of borrow pit to be filled is 75,000 m3.The borrow soil, density is 1540 kg/m3.The…

Q: The soil is uniform if the coefficient of uniformity Cu close to: O 1.2.0 O 2.1.5 O 3.0.1 O 4.1.0…

Q: A 100-gram soil has the following amount adsorbed cations: 5 m.e. of H+; 4 m.e. of Ca2+; 3 m.e. of…

Q: The vol. of soil is 110 cm*. The wet weight of soil is 207 g and the dried weight of soil is 163 g.…

A: Laboratory oven-dry is one of the methods used to know the properties of soil as well as its volume…

Q: to have the following water retention characteristics: Water content at -10 kPa (field capacity) =…

A: Given:- Water content at -10 kPa (field capacity) = 0.15 kg water content at -1500 kPa (wilting…

Q: H.w, A saturateed Soil G,= 2.65 and a mass 175gwas dried, the volume of #he smmple at drying 79.2…

A: Given:- The specific gravity of the saturated soil = Gs = 2.65 The mass of the saturated soil = 175…

Q: The porosity of a soil is 0.35. Given G₁ = 2.70. Calculate: a. Saturated unit weight. (Enter your…

A: Calculate (a) Saturated unit weight (b)Water content

Q: A soil has a water content of 25% and a degree of saturation of 82%. Compute the sp.gr. of the soil…

A: Given data, Water content= w = 25% Degree of saturation= s = 82% Dry unit weight= Yd= 14.23kN/m3…

Q: Q/ Find value of (h) that may cause boiling condition, if saturated density for soil II and III are…

A: Let us analyse the question in step 2.

Q: For a given soil, show that e Ya + Y sat Yw 1 + e

A: To show the following, equation we need to see the formula used in these equations. γsat=G+e1+eγw…

Q: Derive an expression for Degree of Saturation, S in terms of Water content, w, Specific Gravity, Gs,…

Q: 0/If twet density was 18 KN Hm² and dry density was 14 KN/m and porosity#=0-4, then find (St degree…

A: To find the Degree of Saturation-

Q: A soil has a water content of 25% and a degree of saturation of 82%. Compute the sp.gr. of the soil…

Q: A sample Ổf sätura clay a iume of 9. cm and a mass of (0.202 kg). When completely dried at the…

Q: he moist unit weight of a soil is 17.79 kN/cu.m and the porosity is 0.4. If the specific gravity of…

A: γd=Gγw1+eγd=γ1+w

Q: The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 40 and 15,…

A: Soil classification by AASHTO

Q: The soil layers below have a cross section of 100 mm x 100 mm each. The permeability of each soil…

Q: H2 = 0.3’ h = 1.25’ H1 = 0.2’ d = 1.5” H = 0.5’…

Q: A soil has dry unit weight of 15.5 kN/m³, specific gravity of 2.65 and 3 of saturation of 72%.…

Q: 1. A soil with a liquidity index of -0.20 has a liquid limit of 56 percent and a plasticity index of…

A: As per Bartleby policy i can answer only one question at a time. Please upload other questions…

Q: Determine wt of water in kN that must be added to a cubic meter of soil to attain 72% degree of…

Q: d water table dropped by 5 m during the year. Assuming no replenishment, estimate the ic yield of…

Q: A concrete dam retains water to a height of 9 m. It has rows of sheet piling at both heel and toe…

Q: A soil has a known water content of 18% and a specific gravity of 2.68. Determine the degree of…

A: Given data of soil Water content (w) = 18% = 0.18 Specific gravity ( G) = 2.67 Moist unit…

Q: g) Weight of water in KN that must be added per m3 for a 90%-degree saturation h) Mass of water in…

A: Given Data: γb=1960 Kg/m3 γs=2700 kg/m3 Assuming γw=1000 kg/m3 Assuming specific gravity G= 2.7…

Q: Volumes. कणिक Va Viw= LiQuid Sölid We-

A: G=2.65 S=1 (soil is saturated) w=40%

Q: Exercise No.4.5 (G₁ + Se). + For a given soil, show that Y = Yw

Q: In a construction project, the field moist unit weight was 17.5 kN/m³ and the moisture content was…

Q: (b) On a partly saturated soil the following properties are know: e = 0.6 Gs = 2.75 S, = 70% Please…

A: Given data in question Void ratio Degree of saturation Specific gravity To find out water…

Q: Note: Add 0.16 to the results on table before solving. a. Determine the maximum dry unit weight and…

A: table is prepared by adding 0.16 to soil unit weight as per question MOISTURE CONTENT DRY DENSITY…

Q: With the aid of diagram, briefly explain the saturated, unsaturated and dry soil condition of the…

A: Saturated, unsaturated, and dry soil condition are below:

Q: 100g of moist soil hs a mass of 25 g wate, calculate water content?

Q: Problem B: For questions 8 to 11. A cubicmeterof soil in its natural state is 18.907 KN.…

A: Using relationships

Q: C) A specimen of saturated soil ( Gs = 2.72) has a mass of 370 gm after drying the volume was 160…

Q: The porosity of a soil is 0.35. Given G, = 2.70. Calculate: a. Saturated unit weight. (Enter your…

Q: 5. ( ). The moist unit weight of soi is 16.5 kN/m°. GIven that W = 15.0%, and Gs = 2.70. Find : a.…

Q: The silt content of a soil is 60% by weight. In the water content range of 14-28%, the soil is in…

A: Given: Silt content (by weight) = 60% Plastic limit, WP = 28% Liquid limit, WL = 42% Also,…

Q: The soil profile shown below is typical of Miami-Dade County. Estimate the equivalent permeabilities…

A: Each layer permeability are given and so we can find the equivalent permeability in horizontal and…

Q: A partially saturated soil specimen has a total mass M:1360.52 gm 1 and a water content cw:28.35%…

A: The total mass of the soil is M=1360.52 gm. The water content is w=28.35%. The porosity of the soil…

Q: in its natural state. A moist soil has a volume of 9.34×10-3 m3 and weighs 177.61×10-3kN. The…

A: Given information:

Q: Determine the (i) Water content, (ii) Dry density, (iii) Bulk density, and (v) Degree of saturation…

Q: IV. Problems: 1.For a given soil, the followingare known. G = 2.74, moist unit weight = 20.6 KN/cu…

A: Given: The specific gravity of soil is 2.74. The moist unit weight is 20.6 kN/m3. The moisture…

Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

Home workl: for a soil, F.C = 28% by dry weight, wp = 18% by volume,
Allowable depletion (AD) = 50%, AS= 1.35, find: 1- readily available water by
weight 2- Readily available water by volume.
Home work2: from test data of infiltration experiment, D= 2.5 cm @t= 15
minute and D = 8 cm @t= 100 minute, determine: 1- base infiltration rate 2- time
required to accumulate 15 cm depth 3- infiltration rate estimated by (mm/hour) at
time =3 hours
Home work3: A soil has d = 4.5(t) (mm/min) was irrigated by a basin. The
moisture content before irrigation was 20 % by volume. The field capacity (F.C)
was (22 %) by weight, the effective root zone is (1.2 m) and (AS=1.5), find the
time required to complete the irrigation.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given that;

VIEW

Step 2: Therefore, Readily available water by weight/m

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Results of an infiltrometer test on a soil are given below. Determine the Horton's infiltration capacity equation for this soil by identifying the parameters fo, fc and k. Time from start (hr) 0.25 0.50 0.75 1.00 1.25 1.50 1.75 2.0 Infiltration capacity in cm/hr 5.6 3.20 2.10 1.50 1.20 1.10 1.0 1.0 96
PROBLEM NO. 3 SOIL PERMEABILITY A pump test was conducted on a test well drilled into a confined aquifer, with the results showr ** elow. If water was pumped at a steady flow of 205 gal/min, deter... the coefficient of permeability (k in ft/sec) of the permeable soil in the aquifer. 150 ft 75 ft IMPERMEABLE LAYER 20 ft: 12 ft TEST WELL IMPERMEABLE LAYER AQUIFER 16 ft OBSERVATION WELLS Lectures 5
Length of soil sample for constant head permeability test is 30 cm, Area of specimen is 177cm, constant head difference is 50 cm, total volume of water collected in 5 min is 350cm'. Calculate the hydraulic conductivity of the soil. A) 2.85x10'cm/sec D) 1.09x10 cm/sec 8) 1.09x10 cm/sec 9 3.95x10 cm/sec Answer A Submit
The permeameter in a perrneability test setup involves a soil sample 200 mm diameter and a length of 30 mm. The height of water is kept constant at 400 mm. In a duration of 4 min, water was collected in the graduated flask having a volume of 420 cu. cm. Determine the following. Flow Rate Hydraulic gradient Hydraulic conductivity
The infiltration capacity of a soil follows the Horton's exponential model f = C₁ + C₂ e-kt. During an experiment, the intial infiltration capacity was observed to be 200 mm/hr. After a long time the infiltration capacity was reduced to 25 mm/h. If the infiltration capacity after 1 hour was 90 mm/ h the value of the decay rate constant k (in h-¹, up to two decimal places) is
5. A sample of soil is 5 cm high and 8 cm in diameter. It was tested in a constant head permeameter. Water percolates through the soil under a constant head of 45 cm for 8 min. The water collected and weighed. Its weight was recorded as 500 gm. On oven drying the sample of soil, the weight was recorded as 450 gm. If G is 2.65 calculate, Coefficient of permeability. (ii) Seepage velocity of water when the water was under operation.
Water is flowing through three soil layers as shown in Fig. Q2. The cross-section is a square with sides of 100 mm. The hydraulic conductivity (also known as coefficient of permeability) of each soil layer is given in Table Q2. a. What is the equivalent hydraulic conductivity of the three layers? b. Determine the flow rate exiting the system. c. Determine the elevation head diagram, the total head diagram, and the pressure head diagram from point A to point B. Ah = 30 cm h, = 50 cm h2 = 20 cm B D = 10 cm 3.33 cm 3.33 сm 3.33 cm O Datum 45 cm O Datum Fig. Q2: Three-layer permeameter
Question 2 * The permeameter in a permeability test setup involves a soil sample 200 mm diameter and a length of 30 mm. The height of water is kept constant at 400 mm. In a duration of 4 min, water was collected in the graduated flask having a volume of 420 cu. cm. Determine the following. Flow Rate o Hydraulic gradient o Hydraulic conductivity
1. Determine the effective size (d10, in mm) and the uniformity coefficient (UC) for the sand filter media characterized by the sieve analysis results presented in the following table. Sieve opening size (mm) 1.41 1.19 1.00 0.84 0.71 0.59 0.50 0.42 0.35 0.30 % Weight Passing 100 100 94 83 63 35 18 11 8 0
Problem 4. A sample of sand is tested in a constant head permeameter. The sample diameter is 50 mm and its length is 120 mm. Under an applied head of 60 cm, 113 cm³ flows through the sample in 5 minutes. The Mof the sample is 385 grams. Calculate: a. the Darcy coefficient of permeability (k) b. the discharge velocity (v) c. the seepage velocity (v₁)
← Darcy' Law A sand sample of 35 m² cross sectional area and 20 cm long was tested in a constant head permeameter. Under a head of 60 km, the discharge was 120 ml in 6 min. The dry unit weight of sand used for the test was 1120 g. and GS = 2.68 Take Sw = 1 g/ cm³ The hydraulic conductivity (in cm/sec) is × 10-³ X
Example 5.2: - Formation water sample with solids concentrations of calcium (Ca) = = 460 ppm, sulfate (SO4) = 1,400 ppm, and Na plus Cl = 19,000 ppm. %3D Find Equivalent NaCl solution in ppm.