What are the possible phenotypic (P) and genotypic (G) ratios if you cross two parents who are carriers of dominant traits following Mendelian laws of heredity? P: 2:1; G: 3:1 P: 1:2:1; G: 1:3 P: 3:1; G: 1:2:1 P: 3:1; G: 2:1:1
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What are the possible
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P: 2:1; G: 3:1
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P: 1:2:1; G: 1:3
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P: 3:1; G: 1:2:1
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P: 3:1; G: 2:1:1
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- In humans the absence of a cleft chin is dominant to the presence of a cleft chin. Two individuals, both of whom are heterozygous for a recessive allele that causes the cleft chin phenotype have 5 children, what is the probability that 3 of their children would not have a cleft chin and 2 would have a cleft chin? 0.0037 0.026 0.237 0.264There are two types of alleles: Type B1 and Type B2 (In total there are 10) Type B1 has 6 Type B2 has 4 Question: What is the probability of an individual in the offspring generation being homozygous [p^2] for B1? What is the probability of an individual in the offspring generation being homozygous [q^2] for B2? What is the probability of an individual in the offspring gen being heterozygous[2pq]?Why are monozygotic twins who are reared apart so useful in the calculation of heritability?
- Using the HardyWeinberg Law in Human Genetics Suppose you are monitoring the allelic and genotypic frequencies of the MN blood group locus (see Question 2 for a description of the MN blood group) in a small human population. You find that for 1-year-old children, the genotypic frequencies are MM = 0.25, MN = 0.5, and NN = 0.25, whereas the genotypic frequencies for adults are MM = 0.3, MN = 0.4, and NN = 0.3. a. Compute the M and N allele frequencies for 1-year-olds and adults. b. Are the allele frequencies in equilibrium in this population? c. Are the genotypic frequencies in equilibrium?Using the concepts of non-mendelian genetics, what is the phenotypic ratio of the offspring if two heterozygous pea plants with purple flowers are crossed together? O 3 pea plants with light purple flowers: 1 pea plant with a single mixed color for white and purple color. O 3 pea plants with purple flowers: 1 pea plant with light violet flowers. O 1 pea plant with purple flowers: 2 pea plants with white flowers: 1 pea plant with mixed color for white and purple color. O 1 pea plant with purple flowers: 2 pea plants with light purple flowers: 1: pea plant with white flowers.Why are monozygotic twins who are reared apart so useful in the calculation of heritability? What assumption is being made about their respective environment?
- In rabbits, an allelic series helps to determine coat color: C (full color), cch (chinchilla; gray color), ch (Himalayan; white with black extremities), and c (albino; all white). The C allele is dominant to all others, cch is dominant to ch and c, ch is dominant to c, and c is recessive to all the other alleles. This dominance hierarchy can be summarized as C > cch > ch > c. Indicate the phenotypic ratios expected in rabbits with the cross cchch × chc. 1 full color:1 chinchilla 1 full color:1 Himalayan 1 chinchilla:1 Himalayan 3 full color:1 chinchilla 2 full color:1 Himalayan:1 albinoIn humans, the allele for brown (B) eye color is dominant to the allele which causes blue (b) eyes. If a brown-eyed man, whose father had blue eyes marries a brown-eyed woman and the first baby of this couple has blue eyes, answer: What is the genotype of the man? What is the Genotype of the woman? What is the expected genotypic and phenotypic ratio among all possible children?This lab exercise requires that we count certain Mendelian traits among students present in the lab. Your professor will explain each trait being addressed and will then ask students to identify if they are dominant or recessive for that specific trait. The collected traits will then be plugged into the Hardy-Weinberg Equilibrium formula in order to calculate frequency of Homozygous dominant, Heterozygous and Homozygous recessive individuals in the same. p2 + 2pq + q2 = 100 given data: trait: hair swirl 19 individuals total. 10 had the homozygous dominant hair swirl trait: clockwise the nine other were recessive please do a step by step explanation with the calculation using this data, as I am very unfamiliar with what values mean what and the equation itself thank you!
- In rabbits, an allelic series helps to determine coat color: C (full color), cch (chinchilla, gray color), ch (Himalayan, white with black extremities), and c (albino, all-white). The C allele is dominant over all others, cch is dominant over ch and c, ch is dominant over c, and c is recessive to all the other alleles. This dominance hierarchy can be summarized as C > cch > ch > c. The rabbits in the following list are crossed and produce the progeny shown. Give the genotypes of the parents for following cross: Phenotypes of parents Phenotypes of offspring Q. full color × full color 34 full color, 14 albinoIn rabbits, an allelic series helps to determine coat color: C (full color), cch (chinchilla, gray color), ch (Himalayan, white with black extremities), and c (albino, all-white). The C allele is dominant over all others, cch is dominant over ch and c, ch is dominant over c, and c is recessive to all the other alleles. This dominance hierarchy can be summarized as C > cch > ch > c. The rabbits in the following list are crossed and produce the progeny shown. Give the genotypes of the parents for each cross: Phenotypes of parents Phenotypes of offspring a. full color × albino 12 full color, 12 albino b. Himalayan × albino 12 Himalayan, 12 albino c. full color × albino 12 full color, 12 chinchilla d. full color × Himalayan 12 full color, 14 Himalayan, 14 albino e. full color × full color 34 full color, 14 albinoIn rabbits, an allelic series helps to determine coat color: C (full color), cch (chinchilla, gray color), ch (Himalayan, white with black extremities), and c (albino, all-white). The C allele is dominant over all others, cch is dominant over ch and c, ch is dominant over c, and c is recessive to all the other alleles. This dominance hierarchy can be summarized as C > cch > ch > c. The rabbits in the following list are crossed and produce the progeny shown. Give the genotypes of the parents for following cross: Phenotypes of parents Phenotypes of offspring Q. full color × Himalayan 12 full color, 14 Himalayan, 14 albino