We will be solving a problem on trees together! Here's the problem statement: Given the root of a binary tree, invert the tree, and return its root. Function definition for Java: public TreeNode invertTree (TreeNode root) { } Function definition for Python: def invertTree(self, root): #Your code here Announced Test Cases: Test Case 1: Input: Output: 2 3 5 6 8 1 6 5 4 2 Explanation: 1's children are flipped, so 2,8 become 8,2. Their children are also respectively flipped so 5,6 becomes 6,5, and 3,4 becomes 4,3.
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- Write a program in c++ which should create a weighted graph of the values entered by the user andthen write functions that perform the following: 1. Depth first search of source and destination vertex2. Breadth first search of source and destination vertex3. Shortest path search of source and all destination vertices (Dijkstra’s algorithm)4. Shortest path search of source and destination vertex (Dijkstra’s algorithm) The program should present a menu of the options and should run until the user opts to quit.Java Programming Exercise 2 Another co-worker emails you and said she developed a recursive version for doing search in a binary search tree. Here’s the code for the function: public boolean searchRecursive(Node current, int searchValue) { if (current.data == searchValue) return true; else if (current == null) return false; else if (current.data > searchValue) return searchRecursive(current.left, searchValue); else return searchRecursive(current.right, searchValue); } She says that she “keeps getting an error” but unfortunately did not say if it was a compile error or a run-time error (or both). You analyze the code and see there is indeed an error and so you reply with the following: 1. Draw a picture of what a binary search tree would look like after inserting values of 5, 10, 8, 15, 4, 2, and 3 in that order 2. Next, tell her why she gets either a compile time error or run-time error (or both)…please convert to C languange #include<bits/stdc++.h>using namespace std; class tree{ //tree node public: int data; tree *left; tree *right;}; bool hasRootToLeafSum(tree *root, int s){ bool path=false; //declare boolean variable path //base condition checking if(root==NULL && s==0) return true; s-=root->data; //subtract current root value //checking whether leaf node reached and remaining sum =0 if(s==0 && root->left==NULL && root->right==NULL) return true; //recursively done for both subtrees if(root->left){//for left subtree path=path||hasRootToLeafSum(root->left, s); } if(root->right){//for right subtree path=path||hasRootToLeafSum(root->right, s); } return path;} tree* newnode(int data){ //creating new nodes tree* node = (tree*)malloc(sizeof(tree)); node->data = data; node->left = NULL; node->right = NULL;…
- In some environments, such as Genetics, it is not uncommon to have binary trees where the edges between nodes have weights or distances. Give Recursive Pseudocode for how one might calculate the two closest Nodes, returning a minimal distance edge. Assume Nodes and Edges defined as given, in C/++ form (though your answer does not have to be): Structs struct Node String value; Edge* left: Edge* right: Your answer /Input: A binary tree pointer (root node) //Output: Returns an Edge*, Null if there are 1 or 0 nodes. Edge" closest(Node* node){ struct Edgef Node* ancestor: Node* descendant double distance;Help me convert this into java. Thanks a lot! #include<bits/stdc++.h>using namespace std;struct Node{public: int key; struct Node *left,*right;};struct Node *newNode(int data){ Node *temp = (struct Node*)malloc(sizeof(struct Node)); temp->key = data; temp->left = NULL; temp->right = NULL; return temp;}struct Node *insert(Node *node,int key){ if(node == NULL) return newNode(key); if(key<node->key) node->left = insert(node->left,key); else if(key>node->key) node->right = insert(node->right,key); return node;} int maxDepth(Node* node) { if (node == NULL) return 0; else { int lDepth = maxDepth(node->left); int rDepth = maxDepth(node->right); if (lDepth > rDepth) return(lDepth + 1); else return(rDepth + 1); } } int main(){ int t; cin>>t; while(t--) { int n; cin>>n; int…Haskell Textbook: "Programming in Haskell, 2ndEd.", by Graham Hutton Programming in Haskell: data Tree a b = Leaf a | Branch b (Tree a b) (Tree a b) Implement the three functions that traverse the tree inthe given order collecting the values from the tree nodes into a list:preorder :: (a -> c) -> (b -> c) -> Tree a b -> [c]inorder :: (a -> c) -> (b -> c) -> Tree a b -> [c]postorder :: (a -> c) -> (b -> c) -> Tree a b -> [c] Also, show how each of your three functions work step-by-step with the following tree object.tree1 :: Tree Int Stringtree1 = Branch "+"(Branch "*"(Leaf 3)(Branch "+" (Leaf 4) (Leaf 5)))(Branch "+"(Branch "*" (Leaf 6) (Leaf 7))(Leaf 8))Notice that the data type Tree can store different types of values in the leaves than onthe branching nodes. Thus, each of these functions takes two functions as arguments: Thefirst function maps the values stored in the leaves to some common type c, and the secondfunction maps the values…
- Use c++ 1. A Red-Black tree is said to be beautiful if all nodes in the alternate levels of the tree are of the same color. Write a program to check whether a Red-Black tree created from the given input is beautiful or not. Your program should include the following functions. • INSERTREDBLACK (struct node* root, key): Inserts a new node with the 'key' into the tree. • CHECKBEAUTIFUL (struct node* root): Checks whether the given tree is beautiful or not. Input format: Output format: • The output will be 1 if the Red-Black tree is beautiful else -1. Sample Input 1: 9 12 • The first line of input will be an integer 'n' which is the number of nodes in the tree. • After which 'n' integer inputs will be given subsequently which will be the keys of nodes of the tree. The keys are unique and values are in the range [1,1000]. 8 25 3 5 27 22 32 9 Sample Output 1: 1please convert this into c++ import java.util.Iterator;import java.util.NoSuchElementException; public class Queue<Item> implements Iterable<Item> { private int n; // number of elements on queue private Node first; // beginning of queue private Node last; // end of queue // helper linked list class private class Node { private Item item; private Node next; } /** * Initializes an empty queue. */ public Queue() { first = null; last = null; n = 0; } /** * Returns true if this queue is empty. * * @return {@code true} if this queue is empty; {@code false} otherwise */ public boolean isEmpty() { return first == null; } /** * Returns the number of items in this queue. * * @return the number of items in this queue */ public int size() { return n; } /** * Returns the number of items in this queue. * * @return the…All the methods as well as the main method/tester statements must be written in one class. DO NOT write a different class for each method. NOTE: USE PYTHON AD SOLVE BOTH QUESTIONS IF YOU WANT A THUMBS UP. 1. Print elements of all the Nodes of a tree using In-order Traversal. 2. Print elements of all the Nodes of a tree using Post-order Traversal.
- PLEASE WRITE IN C++ Implement a program that uses an array based binary tree (sequential tree) that has a menu with these options: 1.) insert (This option asks the user for a size and then creates the array based tree, filling the tree with characters or integers . Fill the sequential tree as a complete tree and insert keys as children to specific parents, It is also straightforward to insert children to specific parents due to the fixed nature of the parent child relationship, with a parent having children at indexes ( 2 * Parent index ) + 1, and + 2.). 2.) search (asks user for a character to search in the tree then prints if it is in the tree or not.) 3.) quit (exits program)Convert this into Java language ... Thanks! #include<bits/stdc++.h>using namespace std;struct Node{public:int key;struct Node *left,*right;};struct Node *newNode(int data){Node *temp = (structNode*)malloc(sizeof(struct Node));temp->key = data;temp->left = NULL;temp->right = NULL;return temp;}struct Node *insert(Node *node,int key){if(node == NULL)return newNode(key); if(key<node->key)node->left = insert(node->left,key);else if(key>node->key)node->right = insert(node->right,key);return node;}int maxDepth(Node* node){if (node == NULL)return 0;else{int IDepth = maxDepth(node->left);int rDepth = maxDepth(node->right);if (IDepth > rDepth);return(IDepth + 1);else return(rDepth + 1);}int main(){int t;cin> >t;while(t--){int n;cin> >n;int a[n];for(int i=0;i<n;i++)cin> >a[i]; struct Node *root = newNode(a[0]) ;for(int i=1;i<n;i++){insert(root,a[i]);}int d = maxDepth(root);cout< <"max.no.of.person he…Course: Data Structure and Algorithims Language: Java Kindly make the program in 2 hours. Task is well explained. You have to make the proogram properly in Java and attach output screen with program: Restriction: Prototype cannot be change you have to make program by using given prototype. TAsk: classBSTNode { Node left; Node right; int data; publicBSTNode(int _data);// assign data to_data and assign left and right node to null } class BST { BSTNoderoot; public BST();// assign root to null void insert(int data);// this function insert the data in tree which maintain property of BST boolean Search(int key); this function search the data in bst and return true if key is found else return false public void EvenPrint(Node n)// this function only print the data which are even, make this function resursive public void OddPrint(Node n)// this function only print the data which are odd, make this function resursive public void PrimePrint(Node n)// this function only…