Here is the question about mips.Q1). Suppose $s0 stores the base address of word array A and $t0 is associated with m, convert the following instruction into MIPS.          A[240] = A[240+m]Q2).  Suppose $t0 stores the base address of word array A and $s0 is associated with m, convert the following instruction into MIPS.          m= 0          while (m <= 10):              A[m] = A[m+4]*6                 m = m + 6

VDHL simple computer question.

In the MIPS micro-architecture, the PC is incremented for each instruction, during the "Instruction Fetch" stage. The value of the PC may also be updated later within the "Memory Access" phase. * If the value of the PC is: 0x0000 2F1C, what is the value of the PC after you complete the execution of the instruction: ``addi $t0, $s0, $ra``?* <!-- response -->

E In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable code

Here is the question about mips.Q1). Suppose $s0 stores the base address of word array A and $t0 is associated with m, convert the following instruction into MIPS.          A[240] = A[240+m]Q2).  Suppose $t0 stores the base address of word array A and $s0 is associated with m, convert the following instruction into MIPS.          m= 0          while (m <= 10):              A[m] = A[m+4]*6                 m = m + 6