We calculate the probability of getting a homogygous recessive offspring from two heterozygous parents by multiplying the probability of getting the recessive allele from the first parent (1/2) by the probability of getting the recessive allele from the second parent (1/2) and our result is: 3/4 O 1/4 O 1/2

using a Punnett square, what will the offspring look like when the parents are Bb and Bb. B = dominant black hair and b = recessive blue hair. So what percentage of the offspring will have black hair vs blue hair?

If one human parent is heterozygous for blood type A (IAi), and the second parent is heterozygous for blood type B (IBi), what are the expected phenotypic ratios in their children? a. 1/4 with blood type AB, 1/4 with blood type A, 1/4 with blood type B, and 1/4 with blood type O b. 1/4 with blood type A (IAi), 1/2 with blood type AB (IAIB), and 1/4 with blood type B (IBi) c. 1/2 with blood type AB (IAIB), and 1/2 with blood type O (ii) d. 1/2 with blood type A (IAi), and 1/2 with blood type B (IBi) e. 1/2 with blood type A (IAi), and 1/2 with blood type O (ii)

The presence of four equally frequent classes (1:1:1:1) in the progeny suggests two genes, and a double heterozygote x double recessive. A tall, green plant is mated with a short, yellow plant producing: 30 tall, green 28 tall, yellow  32 short, green 27 short, yellow What are the genotypes of the parents?