Given that there is a trait determined by the alleles A and a, where A is dominant, i.e., the presence of A determines the phenotype.  Assume that two parents have four children, and assume that nothing is known about the parents.  One of the four children shows the recessive condition (so its genotype is aa) and the other three show the dominant trait (so their genotype is either Aa or AA).   What can we conclude about the parents? Group of answer choices - at least one parent shows the dominant trait - Both parents are heterozygous - Both parents have at least one recessive allele

This pedigree (below) shows inheritance of a genetic disorder in a family. Assume the trait is rare. What is the mode of inheritance for this trait? [Select] You know this because that mode of inheritance is characterized by: [ Select] • An affected male parent passes the allele to [Select] and [Select] individuals who have the allele express it and and [Select] of his daughters. • An affected female parent passes the allele to [Select] of her daughters. ㅇㅁㅇㅁ î то ◆ of his sons of her so ?

A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8

using a Punnett square, what will the offspring look like when the parents are Bb and Bb. B = dominant black hair and b = recessive blue hair. So what percentage of the offspring will have black hair vs blue hair?

Mendelian Genetics Consider blue eyes in a man as recessive to brown eyes. Show the expected children of a marriage between a blue-eyed woman and brown-eyed man who had a blue-eyed mother. Determine the genotypic ratio (GR) and phenotypic ratio (PR) of the F1 using Punnett Square Method. Hint: Determine the genotypes of each individual first.

In cattle, Horned (H) is completely dominant over the hornless (h) condition. A horned bull is bred to two cows. With cow A, which is hornless, a horned calf is produced. With cow B, also hornless, a hornless calf is produced. What are the genotypes of the bull and the two cows?

Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below.  Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.

A cross is performed between individuals with the following genotypes: Aabb and aaBb. Use a Punnett square and predicted probabilities to answer the following questions. A. What is the probability that an offspring is dominant for the first trait and recessive for the second?  B. What is the probability that an offspring is dominant for both traits?  C. What is the probability that two offspring are dominant for both traits?

If a B is a dominant allele that codes for a trait where the bearer of this allele has a black coat, and b is a recessive allele where the bearer has a brown coat, the recessive genotype will exhibit the phenotype of brown coat, the genotype will have the black coat phenotype, and the dominant genotype will have the black coat phenotype. (Use either heterozygous or homozygous in the blanks.)