Vs, rms = 120v, f = 60Hz, Vd=250VMax power = 250 W, fs = 100KHz, C=440μF= 100m, Ld=lmH, R = 250Vaz = IVsW = 21X60, V5 = √2×1204wC Vd= √2 PoVs112 = 0.015X ILz=0.01Kv1+5/wcvKvOVsR/22 √d 1+5 (22)Vd C=1-7(1)f=jwcv1+5/Wcv→ (2)S=(22)Jazfind Kv, & Wev

Answered: Image /qna-images/answer/bcd49471-960c-4322-8ec6-dad20e3b6dc9.jpg

Vs, rms = 120v, f = 60Hz, vd = 250V Max power = 250 W, &s=100KHZ, C=440μF ~= 100m, Ld=lmH, R = 250 vaz = I2 Vs 4wC Vd / W = 21TX60, V5 = √2 × 120 L=52 Po Kv 1+5/wcv Vs 12= 0.015XIL ^ Vs. R/2 2 √d its (£) C =1→(1) 5=jwav Kv (2) +5/Wcv S=(2x120) Jaz find Kv, & Wev

Vs, rms = 120v, f = 60Hz, vd = 250V Max power = 250 W, &s=100KHZ, C=440μF ~= 100m, Ld=lmH, R = 250 vaz = I2 Vs 4wC Vd / W = 21TX60, V5 = √2 × 120 L=52 Po Kv 1+5/wcv Vs 12= 0.015XIL ^ Vs. R/2 2 √d its (£) C =1→(1) 5=jwav Kv (2) +5/Wcv S=(2x120) Jaz find Kv, & Wev

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter7: Alternating Current, Power Distribution, And Voltage Systems

Section: Chapter Questions

Problem 7RQ

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Question

Vs, rms = 120v, f = 60Hz, Vd=250V
Max power = 250 W, fs = 100KHz, C=440μF
= 100m, Ld=lmH, R = 250
Vaz = I
Vs
W = 21X60, V5 = √2×120
4wC Vd
= √2 Po
Vs
112 = 0.015X IL
z=0.01
Kv
1+5/wcv
Kv
O
Vs
R/2
2 √d 1+5 (22)
Vd C
=1-7(1)
f=jwcv
1+5/Wcv
→ (2)
S=(22)
Jaz
find Kv, & Wev

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