void caseConvert(string &text, char to_case){ //if to_case is 'u' then convert all letters //of text to uppercase and if to_case is 'l' // then convert all letters of text to //lowercase //write your C++ code here

Code is in C++ Instructions Write a program that reads in a line consisting of a student’s name, Social Security number, user ID, and password. The program outputs the string in which all the digits of the Social Security number and all the characters in the password are replaced by x. (The Social Security number is in the form 000-00-0000, and the user ID and the password do not contain any spaces.) Your program should not use the operator [] to access a string element. Input is as follows  highlighted in bold John Doe 333224444 DoeJ 123Password My problem is with my output, i am close with the code, but i have attached what happens on my output and i cannot figure out why? You can see how it prints out multiple times but i am lost?  The terminal image is also attached. Thank you! Here is the code: #include <iostream> //include statement(s)#include <iomanip>#include <string> using namespace std; //using namespace statement(s) void getInfo(string info); //void…

Please help in C++

c++, pleaaaaaase solve the equation

Alphabe. Using C++   Replace any alphabetic character with '_' in 2-character string passCode. Ex: If passCode is "9a", output is:9_Hint: Use two if statements to check each of the two characters in the string, using isalpha().   #include <iostream>#include <string>#include <cctype>using namespace std; int main() {   string passCode;    cin >> passCode;    if (isalpha(passCode.at(9a))) {      passCode = false;   }      if (isalpha(passCode.at(9_)))  {      passCode = true;   }    cout << passCode << endl;   return 0;}).

String with digit. Using C++   Set hasDigit to true if the 3-character passCode contains a digit. #include <iostream>#include <string>#include <cctype>using namespace std; int main() {   bool hasDigit;   string passCode;    hasDigit = false;   cin >> passCode;   hasDigit = true;      if (hasDigit) {      cout << "Has a digit." << endl;   }   else {      cout << "Has no digit." << endl;   }    return 0;}

C++ this is my code so far need help with part 9 #include <iostream> #include <string>   using namespace std;   int GetNumOfNonWSCharacters(const string text); int GetNumOfWords(const string text); int FindText(string text, string sample_text); string ReplaceExclamation(string text); string ShortenSpace(string text);   char PrintMenu(){ char option; cout << "\nMENU"<<endl; cout << "c - Number of non-whitespace characters"<<endl; cout << "w - Number of words"<<endl; cout << "f - Find text"<<endl; cout << "r - Replace all !'s"<<endl; cout << "s - Shorten spaces"<<endl; cout << "q - Quit"<<endl; cout<<endl; cout << "Choose an option:"<<endl; cin >> option; return option; } void ExecuteMenu(string sample_text,char option){ if(option == 'c'){ int nonWSCharacters = GetNumOfNonWSCharacters(sample_text); cout << "Number of non-whitespace characters:…

In C++

C++ PLEASE!!       // FILE: simplestring.h// CLASS PROVIDED: string (a sequence of characters)//// CONSTRUCTOR for the string class:// string(const char str[ ] = "") -- default argument is the empty string.// Precondition: str is an ordinary null-terminated string.// Postcondition: The string contains the sequence of chars from str.//// CONSTANT MEMBER FUNCTIONS for the string class:// size_t length( ) const// Postcondition: The return value is the number of characters in the// string.//// char operator [ ](size_t position) const// Precondition: position < length( ).// Postcondition: The value returned is the character at the specified// position of the string. A string's positions start from 0 at the start// of the sequence and go up to length( )-1 at the right end.//// MODIFICATION MEMBER FUNCTIONS for the string class:// void operator +=(const string& addend)// Postcondition: addend has been catenated to the end of the string.//// void operator +=(const char addend[ ])//…

Code is in C++ Instructions Write a program that reads in a line consisting of a student’s name, Social Security number, user ID, and password. The program outputs the string in which all the digits of the Social Security number and all the characters in the password are replaced by x. (The Social Security number is in the form 000-00-0000, and the user ID and the password do not contain any spaces.) Your program should not use the operator [] to access a string element. Input is as follows  highlighted in bold John Doe 333224444 DoeJ 123Password My problem is with my output, i am close with the code, but i have attached what happens on my output and i cannot figure out why? You can see how it prints out multiple times but i am lost?  The terminal image is also attached. Thank you! Here is the code: #include <iostream> //include statement(s)#include <iomanip>#include <string> using namespace std; //using namespace statement(s) void getInfo(string info); //void…