Using the data provided below, calculate ASuniv for this transformation at 298 K: H₂ (g) --> 2 H (g) AHf for H₂ = 0 kJ/mol AHF for H = 218 kJ/mol So for H₂= 130.5 J/mol.K So for H = 114.6 J/mol.K 830 J/mol.K -1.36 kJ/mol.K None of these answers is correct -633 J/mol.K 1.56 kJ/mol.K

Using the data provided below, calculate ASuniv for this transformation at 298 K: H₂ (g) --> 2 H (g) AHf for H₂ = 0 kJ/mol AHF for H = 218 kJ/mol So for H₂= 130.5 J/mol.K So for H = 114.6 J/mol.K 830 J/mol.K -1.36 kJ/mol.K None of these answers is correct -633 J/mol.K 1.56 kJ/mol.K

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter10: Entropy And The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 10.96PAE

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Question

Using the data provided below, calculate ASuniv for this transformation at 298 K:
H₂ (g) --> 2 H (g)
AHF for H₂ = 0 kJ/mol
AHF for H = 218 kJ/mol
So for H₂= 130.5 J/mol.K
So for H= 114.6 J/mol.K
O 830 J/mol.K
O
O
-1.36 kJ/mol.K
None of these answers is correct
-633 J/mol.K
1.56 kJ/mol.K

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