Using Java program the following: This program should prompt a user for an integer n and then add first n positive integers,  (i.e.  1+2+3+...+n)   The program should use a while loop to do that and print out each intermediate step.   The last formula (given to you) acts as a check.   e.g. Enter the number of integers to add: 10 1 = 1 1+2 = 3 1+2+3 = 6 1+2+3+4 = 10 1+2+3+4+5 = 15 1+2+3+4+5+6 = 21 1+2+3+4+5+6+7 = 28 1+2+3+4+5+6+7+8 = 36 1+2+3+4+5+6+7+8+9 = 45 1+2+3+4+5+6+7+8+9+10 = 55 check: last sum=55 import java.util.Scanner;   public class AddFirstNIntegers{         public static void main(String[] args){         //1. Create a Scanner object named sc;                   //2. Prompt the user to enter the number of positive integers to add                   //3. Read n, the number of integers to add:                   //4. Initialize the counter for the loop (1, 2, or 0 would work, just need to keep it in mind what works better down the road)                  //5. Initialize the variable sum to 1. (Will represent your current sum. We start with 1=1)                  //6. Initialize the String variable s to be "1"          //(Will represent the string for the current sum. e.g. "1+2+3+4+5".)                  //7. Use s and sum to print out (s+" = "+sum) (which should end up being 1 = 1 -- our initial statement)         System.out.println(s+" = "+sum);         //8. create a while loop that in each iteration will add the next         //integer to the previous sum, uppend "+" and next integer to String s,          //and print them out as shown above.         while (...){                      }                  //Check: your last number should be (n+1)*n/2:         System.out.println("     check: "+(n+1)*n/2);            } }

In Coral Language 3.22 LAB: Loops: Countdown until matching digits   Write a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Ex: If the input is: 93 the output is: 93 92 91 90 89 88 Ex: If the input is: 77 the output is: 77 Ex: If the input is: 9 or any number not between 20 and 98 (inclusive), the output is: Input must be 20-98 For coding simplicity, follow each output number by a space, even the last one. Use a while loop. Compare the digits; do not write a large if-else for all possible same-digit numbers (11, 22, 33, …, 88), as that approach would be cumbersome for large ranges.

Write code that iterates while userNum is less than 12. Each iteration: Put userNum to output. Then, put "/" to output. Then, assign userNum with userNum multiplied by 3.

While Loop (PLEASE COMPLETE IN JAVA)Instructions Write a program that finds out the perimeter of a multi-sided shape. Perimeter of a multi-sided shape can be found by adding all of the sides together.The user should enter each number at the command prompt. The user will indicate that he or she isfinished entering the number by entering the number -1.Example:This program will sum a series of numbers.Enter the next number (enter -1 when finished)> 2Enter the next number (enter -1 when finished)> 2Enter the next number (enter -1 when finished)> 1Enter the next number (enter -1 when finished)> 1Enter the next number (enter -1 when finished)> -1The sum of your numbers is 6