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1. Determine the discharge rate through three parallel corrugated metal pipe culverts shown in the sketch below (Use the outlet control). The 48-inch diameter culverts have a Manning, n value of 0.024. The culverts are 80 ft long, laid on a slope of 0.04, and have a projecting inlet and outlet. The culvert inlet bottom elevation is 302 ft with a head water elevation of 308.2 ft and a tailwater elevation of 302 ft. Use Ke = 0.8, Ko = 1.0. What is the discharge through the culvert (Use inlet control) with C₁ = 0.62. HW= 308.2 ft H=6.2 ft 302.0 ft BIBIE 3 Parallel CMP D= 48 inch S=0.04 TW 302.0 ft n=0.024 L = 80 ft

A hydraulic Jump occurs in a trapezoidal channel having b=6ft, m=2, and Q=200cfs.  The flow depth just before the jump is 1 foot. What is the flow depth after the jump? What is the headloss due to the jump? What type of jump is it? What is the length of the jump?

Provide handwritten answer please

A rectangular channel is 4 m wide, and it reduces to 2 m through a hydraulic structure. Assuring the transition to be horizontal and the flow to be frictionless determine the water surface elevations upstream of the constriction when the specific energy at the constriction is 6 m. Assume choking occurs, hence critical flow equations are applicable. Note: Hand written solution is not allowed.

PLEASE SOLVE PARTS (E) AND (F)

Given The channel shown in the figure has a surface of float-finished concrete and is laid on a slope that falls 0.27 m per 100 m of length. Required Calculate the normal discharge for a depth of 1.5 m in m3/s, to the nearest 100th. 2 - 3.0 m

Determine the velocity of flow after hydraulic jump through a 1 m wide channel if the velocity of flow before jump was 2 m/s and the depth was 0.2 m.

Determine critical depth

Last two digit =30