Two parts are assembled as shown in the figure below. Assume that the dimensions x and y are normally distributed with means µx and µy and standard deviations x = 0.4 and oy = 0.3 respectively. The parts are produced on different machines and are assembled at random. (a) If it is desired that the probability of the clearance (i.e., x - y) smaller than 0.09 should be 0.006, (i.e. Pr{(x-y)<0.09} = 0.006) What value of (x-μy) should be specified? (b) Based on the results (x-μy) obtained in (a), calculate the probability that the clearance is greater than 0.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Two parts are assembled as shown in the figure below. Assume that the dimensions x and
y are normally distributed with means µ¸ and µ¸ and standard deviations σx = 0.4 and
oy = 0.3 respectively. The parts are produced on different machines and are assembled at
random.
(a) If it is desired that the probability of the clearance (i.e., x - y) smaller than 0.09 should be
0.006, (i.e. Pr{(x-y)<0.09} = 0.006) What value of (x − μy) should be specified?
-
(b) Based on the results (x-µy) obtained in (a), calculate the probability that the
clearance is greater than 0.
Transcribed Image Text:Two parts are assembled as shown in the figure below. Assume that the dimensions x and y are normally distributed with means µ¸ and µ¸ and standard deviations σx = 0.4 and oy = 0.3 respectively. The parts are produced on different machines and are assembled at random. (a) If it is desired that the probability of the clearance (i.e., x - y) smaller than 0.09 should be 0.006, (i.e. Pr{(x-y)<0.09} = 0.006) What value of (x − μy) should be specified? - (b) Based on the results (x-µy) obtained in (a), calculate the probability that the clearance is greater than 0.
Expert Solution
Step 1: step 1

Given data,

standard deviations

sigma subscript x equals 0.4
sigma subscript y equals 0.3
a right parenthesis space P left square bracket left parenthesis x minus y right parenthesis less than 0.09 right square bracket equals 0.006
f i n d
v a l u e space o f space mu subscript x minus mu subscript y

b right parenthesis space f i n d
p r o b a b i l i t y space t h a t space t h e space c l e a r a n c e space i s space g r e a t e r space t h a n space 0

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