t=t. R2 t = 0 Vin= 10 V (DC) + R1= 10 N Vin R1 R2= 10 N C = 100 µF t1 = 1 ms The switch has been closed for a long time. At t = 0 the switch opens, and at t = t; the switch is closed again. Please answer the following questions. (1) Derive the mathematical expression for ve(t) for 0 <1<1. (2) Calculate the capacitor voltage ve(t) at t = t1. (3) Derive the mathematical expression for ve(t) for t > t1. (4) Sketch the waveform of v-(t) for 0sIS 2 ms. (5) Calculate the time instants when the capacitor voltage ve(t) is equal to 8 V.

Q1 Solve d please Include calculations and steps please

The switch in the circuit shown below was open for a sufficiently long time and no energy is stored in any of the inductors. It is assumed that the switch is suddenly closed at t=0. Draw the equivalent circuit atI-0*. Then determine the time constant, r, and final value, I Determine the current through the voltage source, i(1), for t2 0 Determine the voltage across the resistor R3, v (1), for 120 1. 2. 3. R 1602 R3 1=0 L 0.52H R, 2402 10492 V's + v1) - L3 100V 1.2H 0.8H

Switch S1 has been closed and S2 has open for a long time until the capacitors are fully charged. At t=0, S1 is opened and S2 is closed. If ɛ=12V, C₁=4mF and C₂-8mF, R₁-3.7kQ and R₂-2.07 kQ; what is the current through the capacitor at t=8 seconds in units of mA? Please express your answer using two decimal places. E R₁ www Answer: C₁- a HH b C₂ S₂ R₂