The action of the two switches in the circuit seen in the figure is as follows. For t < 0, switch 1 is in position a and switch 2 is open. This state has existed for a long time. At t = 0, switch 1 moves instantaneously from position a to position b, while switch 2 remains open. Ten milliseconds after switch 1 operates, switch 2 closes, remains closed for 10 ms and then opens. (Figure 1) Part A Find vo(t) 45 ms after switch 1 moves to position b. Express your answer with the appropriate units. 01 UA vo (t)=-1.092 V Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining ?

What type of circuit is this (in terms of the components present in it)?

The following is true in a circuit in DC steady state (select all that apply):   Question 4 options:   Capacitors behave as open circuits   Inductors behave as short circuits   All the voltage and current sources have values that are constant in time   All the voltages and currents in the circuit are constant in time   The circuit is not in the middle of any transitions from one state to another

In the circuit shown in the figure, the switch #2 can be toggled to either position a or b. In position a, and with switch #1 also closed, the inductor (L) and resistor are connected to the source of emf ( &= 16 V). At the moment the switch closes, current begins to flow in the circuit. Given that L = 230 mH and R = 60 2, What is the time constant (7) that describes this charging process? Note that 1 mH = 10-³ H. T= What is the final current flowing in the circuit (after switch #2 is closed and many time constants have passed)? I = S t₁ The time to reach one-half the final current is related to the time constant (- In (¹) ₁ 2 How long would it take (after the switch is closed) for the current to reach one-half its final value? = A S S₂ switch 61 bi i switch S₁ = .693T).. T =