The switch in the circuit shown below was open for a sufficiently long time and no energy is stored in any of the inductors. It is assumed that the switch is suddenly closed at t=0. Draw the equivalent circuit atI-0*. Then determine the time constant, r, and final value, I Determine the current through the voltage source, i(1), for t2 0 Determine the voltage across the resistor R3, v (1), for 120 1. 2. 3. R 1602 R3 1=0 L 0.52H R, 2402 10492 V's + v1) - L3 100V 1.2H 0.8H

In the diagram below, the switch S has been closed for a long time. A) What is the output voltage Vout? What is the charge on the capacitor? b) The switch is opened, so the output voltage increases. What is the time constant that describes the charging of the capacitor in terms of R and C? c) When Vout reaches 10 V, the switch closes and the capacitor begins to discharge. What is the time constant that describes the discharging in terms of R and C? Hint: Apply Kirchhoff's Rules to both loops and the sum of the currents at the junction above the capacitor in the diagram, and use I=dq/dt. If the switch opens when Vout reaches a lower value, say 5V, the capacitor will charge again, and thus one can cycle the voltage with a time constant determined by the circuit: this demonstrates the principle of operation of an electronic timer. 4R S 15 V Vout R

Switch S in in the figure is closed at time t = 0, to begin charging an initially uncharged capacitor of capacitance C= 17.9 µF through a resistor of resistance R = 22.7 Q. At what time is the potential across the capacitor equal to that across the resistor? Number i Units S R C

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