The surface tension of a liquid is being measured with a ring. The ring has an outer diameter of 10 cm and an inner diameter of 9.5 cm. The mass of the ring is 10 g. The force required to pull the ring from the liquid is the weight corresponding to a mass of 16 g. What is the surface tension of the liquid in N/m?

The surface tension of a liquid is being measured with a ring. The ring has an outer diameter of 10 cm and an inner diameter of 9.5 cm. The mass of the ring is 10 g. The force required to pull the ring from the liquid is the weight corresponding to a mass of 16 g. What is the surface tension of the liquid in N/m?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A density fluid p has filled through a tank of diameter, D at a constant rate of v. The bottom of the tank has a feature of a hole with diameter of d. What is the liquid's steady-state height, h, in the tank?
A body requires a force of 100 N to accelerate it at a rate of 0.20 m/s. Determine the mass of the body in kilograms and in slugs.
A particle travels in a straight line with constant acceleration. When s = 4 , v=5 ft/s andwhen s=8, v=7 ft/s. Determine the acceleration ft/s^2.
Solve the given
For the configuration shown on relation of motion of two particles, VA = 100 kph 60° Va#70 kph What is the value of v4?
A bar of uniform cross-section and homogenous material weighing 1000 N and having a cross-section of 1 cm² and length of 1 m, hangs vertically while suspended from one end. The value of Young's modulus of the material, E = 10000 N/mm². The extension of the bar due to its own weight will be
The mass center G of the 1280-kg rear-engine car is located as shown in the figure. Determine the normal force under each tire when the car is in equilibrium. State any assumptions. Answers: -1310 mm-964 mm Normal force under each of the front tires: Nf= Normal force under each of the rear tires: N₁ = i N N
The Azimuth of lines OA and OB are 16° and 332° , the value of the included angle BOA (angle to the left) is