A block of mass m rests on an inclined plane and is attached by a string to the wall as shown in the figure. The coefficient of static friction between the plane and the block is 0.25. The string can withstand a maximum force of 20 N. The maximum value of the mass (m) for which the string will not break and the block will be in static equilibrium is _kg. Take cose = 0.8 and sine = 0.6. Acceleration due to gravity g = 10 m/s m

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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A block of mass m rests on an inclined plane
and is attached by a string to the wall as
shown in the figure. The coefficient of static
friction between the plane and the block is
0.25. The string can withstand a maximum
force of 20 N. The maximum value of the
mass (m) for which the string will not break
and the block will be in static equilibrium is
_kg.
Take cose = 0.8 and sin0 = 0.6.
Acceleration due to gravity g = 10 m/s
m
Transcribed Image Text:A block of mass m rests on an inclined plane and is attached by a string to the wall as shown in the figure. The coefficient of static friction between the plane and the block is 0.25. The string can withstand a maximum force of 20 N. The maximum value of the mass (m) for which the string will not break and the block will be in static equilibrium is _kg. Take cose = 0.8 and sin0 = 0.6. Acceleration due to gravity g = 10 m/s m
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