The shaft of the gate shown in Fig. (1) will fail at a moment of 135 kN.m. Determine maximum value of liquid depth 'h'. S.G= 1.05 gate width 1m
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- A trough whose cross section is a trapezoid is b = 8 m across at the bottom, a = 12 m across at the top, and 4 m deep. If the trough is filled to 1 m with water, what is the force due to water pressure on one end of the trough? F a C (Hint: Using SI units, pg = 9800 N/m³.) (Use decimal notation. Give your answer to two decimal places.) Incorrect b 55533.33 N13 см Vaxn's 29cm 26cm !- Stancs X ax. 5. Find The location of conter of gravityA vessel is in the form of an inverted regular square pyramid of altitude 9.87 in. and base edge 6.27 in. The depth of the water it contains is 6 in. a. How much will the surface rise when 1 pt. of water is added? ( 1 gal.=231 cu.in.) b. Find the wetted surface when the depth of water is 9.23 in.?
- depth of water on the upstream and downstream sides of the lock are 6 m and 4 m respectively. Find: is 10 m. Each gate is supported by two hinges located at I m and 5 m above the bottom of the lock. The 24. The end gates ABC of a lock are 8 m high and when closed make an angle of 120°. The width of lat gate, and (i) magnitude of the hinge reactions. [Ans. () 79.279 kN, () Ry=27.924 kN, R,= 51.3SAN sides of the gates are 4 m and 3 m respectively, determine : (i) the magnitude of resultant pressure on cat gates are closed, they make an angle of 120°. The width of the lock is 4 m. If the depths of water on the rwe 4m as shown in Fig. 3.60. Consider width of the gate unity. () Resultant water force on cach gate. 21. Find the horizontal and vertical components of the water pressure exerted on a tainter gate of [Ans. F,= 19.62 kN, F, =710244N] 22. Find the magnitude and direction of the resultant water pressure acting on a curved face of a dam which is shaped WATER SURFACE according to the…EXERCISE 2 The gate is 1.8 m into the paper. Compute: 1. The resultant hydrostatic force F. 2. The depth hp at which the hydrostatic force acts. 2.9 m hp F 1.9 m 1m 1.8 m haA rectangular sluice gate is situated on the vertical wall of lock. The vertical side of the sluice is (d) meters in length and depth of centroid of area is (P) meter below the water surface. Prove the depth of pressure is equal to = P + 12 P X= P •G d. to %3D
- 1.) Water backs up behind a concrete dam as shown in the figure. Leakage under the foundation gives a pressure distribution under the dam as indicated. If the water depth, h, is too great, the dam will topple over about its toe (point A). Base on a per unit length analysis of the dam with specific weight of the concrete as 150 lb/ft³, determine the maximum water depth for the following widths of the dam. L = 30 ft. Water 80 ft Water h,= 10 ft PA= yh Pg=yhQ1. Find the horizontal thrust of the water on each foot of width of the sluice gate, given y₁ = 7 ft, y2 = 1.2 ft, and y3 = 1.4 ft. Neglect friction Water Y3 Gate 17The rectangular lamina with breadth = 40 mm, depth = 60 mm. The Ixx value is mm4 Select one: O 10.66 x 104 O 24 x 104 O 72 x 104 O 32 x 104 Friction force always acts in a direction to the direction of motion. Select one: O inear O normal O opposite O perpendicular
- A square hole is made in a circular lamina, the diagonal of the square is equal to the radius of the circle as shown in below figure the shift in the centre of gravity is Or (-0.75)/(-0.5) r (-0.25)/(-0.75) Or (-0.5)/(-0.25) r(-0.5)/(-0.75)Find the horizontal pressure acting at the face of the at 30ft depth with a total depth of 40ft.... 5m X 1m Water A wooden beam of specific gravity 0.64 is 150mm x 150mm x 5m is hinged as shown on one side and the other side floats on water. Take note that the location of the center of gravity of the beam (weight) is at the middle of the entire beam while the buoyant force will be located at the center of the beam that is only submerged in water. Determine the: a) the length of the beam "X" that is submerged in water and b) the angle the beam it creates along the horizontal, e A x = 2.3m B) x = 3.0m e = 30 degrees X = 2.7m E x = 2.0m F e = 19.47 degrees G e = 25.77 degrees (H) e = 21.74 degrees