Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Determine what is the most likely mode of inheritance of this disease (whether it is inherited as the result of an X-linked dominant or X-linked recessive trait). Use "A" for the allele associated with the dominant phenotype, and lowercase "a"" for the allele associated with the recessive phenotype. Write the most probable genotype for each individual based on the mode of inheritance you have determined. Show how all the partners are crossed and the expected offspring produced (You may use Punnett Square). OT I OT do IIarrow_forwardPhenylketonuria is one of the most common recessive genetic disorders in humans. Infants with PKU are missing an enzyme called phenylalanine hydroxylase, needed to break down an amino acid called phenylalanine. If a strict diet that minimizes the amount of phenylalanine in the diet is not followed, a severe nervous disorder may result. If two heterozygous parents have a child, hah is the possible genotype and phenotype for this individual?arrow_forwardIn humans the allele coding for normal metabolism of the amino acid phenylalanine (P) is dominant over the recessive autosomal allele (p) that causes the disease phenylketonuria, or PKU. Without treatment, this disease is characterized by brain damage due to the failure of the gene to code correctly for the enzyme phenylalanine hydroxylase. If a man marries a woman and both are heterozygous for hemophilia and heterozygous for PKU, what is the chance that they will have a child afflicted by both diseases? Your response MUST include:(a): list the traits involved (example: Color: Blue- B (dominate) Green - b (recessive) -Do not use this example as this is not part of the problem(b): identify if its a monohybrid or dihybrid cross and why (use prompt above) (c): create a punnet square that represents the problem abovearrow_forward
- Use the following information to answer the next question. The shape of the fruit of summer squash plants is determined by the interaction of two genes. The genotypes and corresponding phenotypes for the shapes of summer squash are given below. a. DDee b. ddee In order to determine the genotype of a squash with disc-shaped fruit a plant breeder would cross the disc- shaped plant with which of the following? Select one: c. ddEE Genotype D_E_ D_ee, ddE_ ddee d. DDEE Phenotype disc-shaped fruit sphere-shaped fruit long-shaped fruitarrow_forwardCystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tellarrow_forwardOne form of the bleeding disorder known as von Willebrand disease is an autosomal recessive disease. A man who is a carrier marries a woman who is also a carrier of the disease. (a) What percentage of their children are likely to have a disease phenotype? (b) What percentage of their children are likely to have a normal phenotype? (c) What percentage of their children are likely to be carriers of the disease?arrow_forward
- Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?arrow_forwardA SNP marker is found linked to the cystic fibrosis gene. Cystic fibrosis is an autosomal recessive disease. A couple plans to have children together and both are carriers for the cystic fibrosis gene but do not have the disease themselves. They are both A1/A2 at the SNP and the A2 allele is linked with the allele causing cystic fibrosis. Assuming no crossing over between the SNP and the disease gene, what genotypes in the offspring could result that would cause cystic fibrosis? O A1-cf, A1 - cf O A2-cf, A2 - cf O A1 - CF, A1 - CF O A1 - CF, A2 - cfarrow_forwardAchondroplasia is a form of dwarfism in humans. It is caused by a mutant allele of the fibroblast growth factor receptor 3 gene ( FGFR3) that produces an overactive protein. Having one copy of the mutant allele results in dwarfism. Two copies of the mutant allele results in death before birth. If a man with Achondroplasia marries a woman who is Sickle Cell Anemia carrier and they have a child together, what is the probability that their child will Achondroplasia AND be a Sickle Cell Anemia carrier? ½ 2/3 ¼ 1 ½ 1/16arrow_forward
- Sickle Cell Anemia is caused by an abnormal form of haemoglobin, the part of the red blood cell that carries oxygen around the body. The red blood cells become stiff and block blood vessels, causing pain and damage and quickly destroying blood cells, leading to anemia. It is estimated that approximately 1 in 32 000 people in Canada are affected with sickle cell anemia.The disorder occurs when a person inherits two recessive genes for the condition. What are the frequencies of the recessive disease allele and the dominant normal allele in the population's gene pool? Select one: a. Recessive Allele Dominant Allele 0.559% 99.4% b. Recessive Allele Dominant Allele 5.59% 94.4% c. Recessive Allele Dominant Allele 0.313% 99.7% d. Recessive Allele Dominant Allele 0.00313% 99.9%arrow_forwardSickle cell anemia causes hemoglobin, the oxygen - carrying molecule of red blood cells, to be misshapen resulting in disease. "H" is the normal hemoglobin allele and "h" is the allele for sickle - cell shaped hemoglobin. In order to get the disease, a person must have a recessive genotype (hh). Two people with normal red blood cells are carriers of the gene - they have m genotypes Hh. Questions: a. What are the possible genotypes of the eggs the woman can produce? b. What are the possible genotypes of the sperm the man can produce? c. What is the genotypic ration for the offspring? d. What is the phenotype ratio for the offspring? e. What is the couple's chance of having a child a sickle cell anemia?arrow_forwardIn humans, ABO blood types refer to glycoproteins in the membranes of red blood cells. There are three alleles for this autosomal gene: IA, IB, and i. The IA allele codes for the A sugar, The IB allele codes for the B sugar, and the i allele doesn't code for any sugar. IA and IB are codominant, and i is recessive to both IA and IB. If an individual with type AB blood has a child with an individual with type O blood, what blood types could their children possibly have?arrow_forward
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