The images attached show a parental cross that is homozygous wild female x white male. F1 were intercrossed to produce the F2 generation as indicated below:Wild Female: 416 Wild Male: 192 White Female: 0 White Male: 192A chi-square analysis was done and an image was also attached.Please discus what conclusions can be made based on the data/findings. What inheritance pattern is this? Phenotypes FractionExpected2/4WildFemaleWild MaleWhiteFemaleWhiteMaleTotal1/41/41Observed Expected(0)(E)4164001920192800200200800Deviation(D)16-8-80D²2566464D²/E0.640.320.32X² = 1.28 P:F₁:F₂:X+X+XXXwY1 X+XW 1 X+Y2 X+X 1 X+Y :1 XWYFigure 1. Monohybrid cross for the inheritance of the white mutation. Homozygous wild-type (red-eyed) females were crossed with white-eyed males. The resulting F₁ generation were then crossed togenerate the F₂ generation, resulting in a ratio of 2 red-eyed females (X*X* and X*X³): 1 red-eyed male(X+Y): 1 white-eyed male (XY).

Name: The images attached show a parental cross that is homozygous wild fema
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: The images attached show a parental cross that is homozygous wild female x white male. F1 were intercrossed to produce the F2 generation as indicated below:Wild Female: 416 Wild Male: 192 White Female: 0 White Male: 192A chi-square analysis was done

Chi-square (X2) test is performed to compare the observed data of an experiment with the expected…

Science

Biology

The images attached show a parental cross that is homozygous wild female x white male. F1 were intercrossed to produce the F2 generation as indicated below: Wild Female: 416 Wild Male: 192 White Female: 0 White Male: 192 A chi-square analysis was done and an image was also attached. Please discus what conclusions can be made based on the data/findings. What inheritance pattern is this?

The images attached show a parental cross that is homozygous wild female x white male. F1 were intercrossed to produce the F2 generation as indicated below: Wild Female: 416 Wild Male: 192 White Female: 0 White Male: 192 A chi-square analysis was done and an image was also attached. Please discus what conclusions can be made based on the data/findings. What inheritance pattern is this?

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 32CTQ: In Section 12.3, ''Laws of Inheritance," an example of epistasis was given for the summer squash....

See similar textbooks

Similar questions

+ ec +/Y + + w/Y y ec +/Y + ec +/y ec w ++ w/y ec w у ес +у ес и Determine the order in which the three loci y, ec, and w Occur on the chromosome and prepare a linkage map. 7.22 A cross involving X-linked genes was made between yellow, bar, vermilion female fies and wild males, and the F1 females were crossed with y B v males. The following phenotypes were obtained when 1000 progeny were exam- ined: Dra ord ma the 7.2 546 244 160 50 + + + + Bv y Bv y+ + y+v y B+ and an and and and +B + re + + v ge Determine the order in which the three loci occur on the chromosome and prepare a linkage map. 7.23 Female Drosophila heterozygous for ebony (e"le), scarlet (st*/st), and spineless (ss*/ss) were testcrossed, and the following progeny were obtained: PROGENCY PHENOTYPES NUMBER ir Wild type Ebony Ebony, scarlet Ebony, spineless Ebony, scarlet, spineless Scarlet 67 8. 68 347 78 368 Scarlet, spineless Spineless (a) Are these genes linked? Justify your answer. (b) Write the genes given on a…
n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines sing the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspring
Name: Genetic Crosses that Involve 2 Traits In rabbits, black hair is dominant to brown hair. Also in rabbits, long straight ears are dominant to floppy ears. These letters represent the genotypes and phenotypes of the rabbits: BB = black hair EE = long ears Ee = long ears ee = floppy ears Bb = black hair bb = brown 1. A male rabbit with the genotype BBee is crossed with a female rabbit with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. How many out of 16 have black hair Be Be Be Be and long ears? How many out of 16 have black hair bE and floppy ears? be How many out of 16 have brown hair and long ears? bE How many out of 16 have brown hair be and floppy ears? 2. Show the cross: GgBb x ggBb How many out of 16 have black hair and long ears? How many out of 16 have black hair and floppy ears? How many out of 16 have brown hair and long ears? How many out of 16 have brown hair and floppy ears?
In com, male sterility is controlled by maternal cytoplasmic elements. However, the presence of a nuclear fertility restorer gene (F_) restores fertility to male sterile lines. a. What are the crosses male sterile female x FF male? Give the genotypes and phenotypes of the offspring in each cross. Explain.
In Drosophila, the gene loci for curved wings and purple eyes are 20 centimorgans (map units) apart from each other on an autosomal chromosome. Wild-type flies were mated with double mutant flies with cv cv p p genotypes and curved wing/purple eye phenotypes. AlIl of the F1 flies had wild type phenotypes. The F, flies were crossed with double mutant flies with cv cv p'p genotypes and curved wing/purple eye phenotypes. What are the predicted percentages of flies in the F2 generation with wild type wings and eyes, curved wings and wild type eyes, wild type wings and purple eyes, and curved wings and purple eyes?
In humans, the genes for red-green color blindness (R = normal, r = color blind) and hemophilia A (H = normal, h = hemophilia) are both X-linked and only 3 map units apart. Suppose a woman has four sons, and two are color blind but have normal blood clotting and two have hemophilia but normal color vision. What is the probable genotype of the woman? HR/hr Hr/hr hr/hR Hr/hR HR/Hr
SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg 305 b + lg b v lg + + lg b v + 148 58 + + + 62 + y + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.
n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines Using the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspring
ABO blood type is determined by three alleles: *, 18, and i. On a separate chromosome, anotherset of alleles determines the Rhesus factor: D and d.A woman with blood type A, who is heterozygous for both blood type and Rhesus factor, had achild with a man with blood type B, who is heterozygous for both blood type and Rhesus factor. What is the percentage chance that this child is blood type B and heterozygous for both traits? Record your answer as a percentage rounded to one decimal place.
In Drosophila melanogaster, red eyes are dominant over white and the variation for this characteristic is on the X chromosome. Vestigial wings (v) are recessive to normal (V) for an autosomal gene. Predict the appearance of offspring of the following crosses: XW/Xw V/v×Xw/Y v/v, Xw/Xw V/v × XW/Y V/v.
Monohybrid Cross: 1) In dogs, wire hair (S) is dominant to smooth (s). a. In a cross between a homozygous wire-haired dog with a smooth haired dog what are the genotypes and phenotypes of the F1 generation? b. If a brother and sister from the F1 generation are crossed what is the expected ratio of wire-haired to smooth-haired dogs produced from this cross?
In fruit flies, you are mapping three genes in a three point cross. The mutants are hairy body (h), sepia colored eyes (se) and female sterility (g). You cross a heterozygous parent with a homozygous recessive parent and obtain the following results: Type Number h se g. 5 + se + 450 + se g 27 ++g_ h se + + + + h + g. h + + TOTAL is the gene in the middle and the distance in map units between se and g is Oh; 16.4 se; 7.1 Oh; 7.1 70 82 7 327 32 1000 se; 16.4