The composite bar, firmly attached to unyielding supports, is initially stress free. What maximum axial load P can be applied if the allowable stresses are 100 MPa for aluminum and 140 MPa for steel? Bronze Steel A = 1125 mm² E = 83 GPa A = 1800 mm2 E = 200 GPa %3D %3D %3D -450 mm- 360 mm
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- The composite bar, firmly attached to unyielding supports, is initially stress free. What maximum axial load P can be applied if the allowable stresses are 80 MPa for aluminum and 144 MPa for steel? Steel Aluminum A = 1125 mm2 E = 70 GPa A = 1800 mm? E = 200 GPa 450 mm- 360 mm-In the connection shown, 1/4-in. side and end fillet welds are used to connect the 3-in.-by-1 in. tension member to the plate. The applied load is 60,000 lb. Find the required dimension L. The steel is ASTM A36 and the electrode used is an E70. - Fillet welds L 3" Activate Windows Go to Settings to activate Wir TABLE 19.2 Allowable stresses in ksi (MPa) 12: 12/1 DELL end F12 insert prt sc F10 home F11 F6 F8 F9 F3The composite bar is stress-free before the axial loads P1 and P2 are applied. Assuming that the walls are rigid, calculate the stress in each material if P1 = 150 kN and P2 = 90 kN. %3D Aluminum Steel Bronze A = 900 mm| A = 2000 mm| A = 1200 mm? E = 83 GPa E = 70 GPa | E = 200 GPa P1 500 mm '250 mm' 350 mm
- The composite bar shown is firmly attached to unyielding supports. An axial load P- 269 kN is applied at 28 °C. Find the stress in the aluminum at 68 C. Assume a= 11.7 um/(mC) for steel and 23 um/{mC) for aluminum. Given: Ea =70 GPa, Aa - 968 mm, La - 228 mm, Es = 211 GPa, As=1,265 mm, Ls= 374 mm, Answer must be in MPa. Aluminum Steel La LsThe composite bar is firmly attached to unyielding supports. Compute the stress (psi) in each material caused by the application of the axial load P = 50 kips Aluminum A = 1.25 in? E = 10 x 10° psi Steel A = 2.0 in? E = 29 x 10° psi 15 in 10 in06. The composite bar, firmly attached to unyielding supports, is initially stress-free. What maximum axial load P can be applied if the allowable stresses are 10 ksi for aluminum and 18 ksi for steel? Steel A = 2.0 in.2 Aluminum A = 1.25 in.2 E = 10 x 10° psi E = 29 x 10° psi SUMMARY OF ANSWERS P kips -15 in- -12 in.-
- 06. The composite bar, firmly attached to unyielding supports, is initially stress-free. What maximum axial load P can be applied if the allowable stresses are 10 ksi for aluminum and 18 ksi for steel? Steel Aluminum A = 1.25 in.? E = 10 x 106 psi A = 2.0 in.2 E = 29 x 106 psi SUMMARY OF ANSWERS P kips -15 in: -12 in.- CS Scanned with CamScannerThe composite bar is stress-free before the axial loads P, and P, are applied. Assuming that the walls are rigid, calculate the stress (MPa) in each material if P1 = 150 kN and P2 = 90 kN Aluminum A = 900 mm A = 2000 mm A = 1200 mm? E = 70 GPa | E= 200 GPa Steel Bronze E = 83 GPa P1 500 mm 250 mm' 350 mm1. Three metal strips, each 40 mm height, are bonded together to form the composite beam shown. The modulus of elasticity is 210 GPa for the steel, 105 GPa for the brass, and 70 GPa for the aluminium. If the allowable bending stress for the aluminum (Gallow)al= 100 MPa, for the steel (Gallow)st 150 MPa and (Gallow)br=200 MPa for brass determine the maximum allowable intensit of w of the uniform distributed load. 2w 2m Aluminum Brass Steel 40 mm- 10 mm 10 mm 20 mm
- 8. The composite bar is stress-free before the axial loads P1 and P2 are applied. Assuming that the walls are rigid, calculate the stress in each material if P1 = 153 kN and P2 = 80 kN. Steel A = 900 mmA = 2000 mm A = 1200 mm2 E - 200 GPa Aluminum Bronze E - 70 GPa E- 83 GPa 500 mm 250 mm' 350 mmCalculate the steel ratio that will produce a tension-controlled failure if compressivestrength f’c = 28 MPa and steel yield strength fy the answer is 0.02167 but i don't know how to solve it please helpQ Search MT ACTIVITY 2M Close Activity File Home Insert Draw View Help Open in Desktop App O Tell me what you want to do v 11 ev Av A A Styles v E Tags v abc v Calibri ... SW The composite bar shown in Fig. P-273 is firmly attached to unyielding supports. An axial force P = 50 kips is applied at 60°F. Compute the stress in each material at 120°F. Assume a = 6.5 × 10- Teams Assignments 国 Calendar Calls 6 in/(in-°F) for steel and 12.8 x 10-6 in/(in-°F) for aluminum. Files Aluminum A = 2 in? E = 10 x 10° psi Steel A = 3 in? E = 29 x 10° psi ... 15 in 10 in 田 Help