The composite bar, firmly attached to unyielding supports, is initially stress free. What maximum axial load P can be applied if the allowable stresses are 80 MPa for aluminum and 144 MPa for steel? Steel Aluminum A = 1125 mm2 E = 70 GPa A = 1800 mm? E = 200 GPa 450 mm- 360 mm
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- The composite bar, firmly attached to unyielding supports, is initially stress free. What maximum axial load P can be applied if the allowable stresses are 100 MPa for aluminum and 140 MPa for steel? Bronze Steel A = 1800 mm² A = 1125 mm? E = 83 GPa %3D E = 200 GPa %3D P -450 mm- 360 mm·In the connection shown, 1/4-in. side and end fillet welds are used to connect the 3-in.-by-1 in. tension member to the plate. The applied load is 60,000 lb. Find the required dimension L. The steel is ASTM A36 and the electrode used is an E70. - Fillet welds L 3" Activate Windows Go to Settings to activate Wir TABLE 19.2 Allowable stresses in ksi (MPa) 12: 12/1 DELL end F12 insert prt sc F10 home F11 F6 F8 F9 F306. The composite bar, firmly attached to unyielding supports, is initially stress-free. What maximum axial load P can be applied if the allowable stresses are 10 ksi for aluminum and 18 ksi for steel? Steel Aluminum A = 1.25 in.? E = 10 x 106 psi A = 2.0 in.2 E = 29 x 106 psi SUMMARY OF ANSWERS P kips -15 in: -12 in.- CS Scanned with CamScanner
- 1. Three metal strips, each 40 mm height, are bonded together to form the composite beam shown. The modulus of elasticity is 210 GPa for the steel, 105 GPa for the brass, and 70 GPa for the aluminium. If the allowable bending stress for the aluminum (Gallow)al= 100 MPa, for the steel (Gallow)st 150 MPa and (Gallow)br=200 MPa for brass determine the maximum allowable intensit of w of the uniform distributed load. 2w 2m Aluminum Brass Steel 40 mm- 10 mm 10 mm 20 mm06. The composite bar, firmly attached to unyielding supports, is initially stress-free. What maximum axial load P can be applied if the allowable stresses are 10 ksi for aluminum and 18 ksi for steel? Steel A = 2.0 in.2 Aluminum A = 1.25 in.2 E = 10 x 10° psi E = 29 x 10° psi SUMMARY OF ANSWERS P kips -15 in- -12 in.-Situation No. 2 A bronze bar is fastened between a steel bar and an aluminum bar as shown below. Axial loads are applied at the positions indicated. Find the largest value of P that will not exceed an overall deformation of 3.0 mm, or the following stresses: 140 MPa in the steel, 120 MPa in the bronze, and 80 MPa in the aluminum. Assume that the assembly is suitably braced to prevent buckling. Use Est = 200 GPa, Eal = 70 GPa, and Ebr = 83 GPa. Bronze Steel A = 480 mm? Aluminum A = 650 mm A = 320 mm 3P 4P 2P 1.0 m 2.0 m 1.5 m
- Q Search MT ACTIVITY 2M Close Activity File Home Insert Draw View Help Open in Desktop App O Tell me what you want to do v 11 ev Av A A Styles v E Tags v abc v Calibri ... SW The composite bar shown in Fig. P-273 is firmly attached to unyielding supports. An axial force P = 50 kips is applied at 60°F. Compute the stress in each material at 120°F. Assume a = 6.5 × 10- Teams Assignments 国 Calendar Calls 6 in/(in-°F) for steel and 12.8 x 10-6 in/(in-°F) for aluminum. Files Aluminum A = 2 in? E = 10 x 10° psi Steel A = 3 in? E = 29 x 10° psi ... 15 in 10 in 田 HelpA beam is reinforced for tension only unless its required steel ratio is _________ the maximum steel ratio required by NSCP 2015. Select one: a. greater b. smaller If the strain in the compression bar is less than that of the yield strain, is the value of fy equal to fs'? Select one: a. no b. yes1. Three metal strips, each 40 mm height, are bonded together to form the composite beam shown. The modulus of elasticity is 210 GPa for the steel, 105 GPa for the brass, and 70 GPa for the aluminium. If the allowable bending stress for the aluminum (Gallow)al= 100 MPa, for the steel (Gallow)s=150 MPa and (Gallow)b= 200 MPa for brass determine the maximum allowable intensit of w of the uniform distributed load. 2w Aluminum 2w 10 mm Brass 10 mm Steel 20 mm 2m - 40 mm
- The composite bar shown is firmly attached to unyielding supports. An axial load P- 269 kN is applied at 28 °C. Find the stress in the aluminum at 68 C. Assume a= 11.7 um/(mC) for steel and 23 um/{mC) for aluminum. Given: Ea =70 GPa, Aa - 968 mm, La - 228 mm, Es = 211 GPa, As=1,265 mm, Ls= 374 mm, Answer must be in MPa. Aluminum Steel La LsThe composite bar is firmly attached to unyielding supports. Compute the stress (psi) in each material caused by the application of the axial load P = 50 kips Aluminum A = 1.25 in? E = 10 x 10° psi Steel A = 2.0 in? E = 29 x 10° psi 15 in 10 inA composite bar is rigidly attached to the wall at A as shown in the figure. Axial loads are applied at the positions indicated. 3 m 2.5 m C 1200 kN 900 kN 80mmØ 100mmØ E = 83 GPa Bronze E = 200 GPa Steel Which of the following most nearly gives the deformation of C? a. -0.7855 mm О Ъ. +0.8575 mm c. +0.7855 mm o d. - о.8575 mm