The balanced equation for the reaction of aqueous Pb(ClO,), with aqueous NaI is Pb(CIO,),(aq) + 2 NaI(aq) PbI (s) + 2 NaCIO,(aq) What mass of precipitate will form if 1.50 L of concentrated Pb(Cio,), is mixed with 0.650 L of 0.250 M NaI? Assume the reaction goes to completion. mass of precipitate:

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The balanced equation for the reaction of aqueous Pb(ClO₃)₂ with aqueous NaI is

\[ \text{Pb(ClO}_3\text{)}_2(\text{aq}) + 2 \text{NaI(aq)} \rightarrow \text{PbI}_2(\text{s}) + 2 \text{NaClO}_3(\text{aq}) \]

What mass of precipitate will form if 1.50 L of concentrated Pb(ClO₃)₂ is mixed with 0.650 L of 0.250 M NaI? Assume the reaction goes to completion.

\[ \text{mass of precipitate:} \_\_\_\_\_\_ \text{g} \]
Transcribed Image Text:The balanced equation for the reaction of aqueous Pb(ClO₃)₂ with aqueous NaI is \[ \text{Pb(ClO}_3\text{)}_2(\text{aq}) + 2 \text{NaI(aq)} \rightarrow \text{PbI}_2(\text{s}) + 2 \text{NaClO}_3(\text{aq}) \] What mass of precipitate will form if 1.50 L of concentrated Pb(ClO₃)₂ is mixed with 0.650 L of 0.250 M NaI? Assume the reaction goes to completion. \[ \text{mass of precipitate:} \_\_\_\_\_\_ \text{g} \]
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