The aluminum rod AB (G = 27 GPa) is bonded to the brass rod BD (G= 39 GPa). Knowing that portion CD of the brass rod is hollow and has an inner diameter of 40 mm, determine the angle of twist at A. 60 mm TB 1600 N-m 36 mm TA 250 mm = 800 N·m A 400 mm 375 mm Then, determine the maximum and minimum shearing stress in shaft CD.

The aluminum rod AB (G = 27 GPa) is bonded to the brass rod BD (G= 39 GPa). Knowing that portion CD of the brass rod is hollow and has an inner diameter of 40 mm, determine the angle of twist at A. 60 mm TB 1600 N-m 36 mm TA 250 mm = 800 N·m A 400 mm 375 mm Then, determine the maximum and minimum shearing stress in shaft CD.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The plate of thickness, t 5 mm, is loaded with the following stress; o, = 100 MPa, o, = -60 MPa, E = 200 GPa, v 0.33. If a = 160 mm, and b= 200 mm, y C Calculate the change in the length (mm) of AB.
The compound shaft consists of a solid aluminum segment (1) and a hollow brass segment (2) that are connected at flange B and securely attached to rigid supports at A and C. Aluminum segment (1) has a diameter of 0.55 in., a length of L₁ = 40 in., a shear modulus of 3800 ksi, and an allowable shear stress of 5.8 ksi. Brass segment (2) has an outside diameter of 0.45 in., a wall thickness of 0.15 in., a length of L₂ = 30 in., a shear modulus of 6400 ksi, and an allowable shear stress of 8.2 ksi. Determine: (a) the allowable torque Te that can be applied to the compound shaft at flange B. (b) the magnitudes of the internal torques in segments (1) and (2). (c) the rotation angle of flange B (relative to support A) that is produced by the allowable torque TB. L₁ L2 TB (1) Answer: (a) TB= (b) T₁ = T2= (c) OB= B lb-ft lb-ft lb-ft rad (2) C
If the maximum bending stress at section a–a is not allowed to exceed an allowable stress of 220 MPa, determine the maximum allowable force P that can be applied to the end E.
For the shown Fig., find the maximum shearing stress in bronze part of the shaft. * Steel d= 200mm G= 80GPa Bronze d= 100mm d= 100mm G= 40GPa G= 30GPA 2KN.m Aluminum 8KN.m 3kN.m 3m 2m 1.5m +
2. Member AB shown in the figure supports a 5 N/mm uniformly distributed load and 4kN concentrated load as shown in the figure. Determine the position x of these loads so that the average tensile stress in the tie rod AC is equal to 90% of the compressive stress at the smooth support B. The rod has a diameter of 19 mm and the contact area at is 700mm². (Hint: quadratic formula) B A X 5 N/mm 4 kN 300mm B
4. A rigid block of having a weight M is suspended by symmetrically placed rods. Each copper rod has an area of 1200 sq.mm: E= 125,000 MPa and the allowable stress is 90 MPa. The steel rod has an area of 1500 sq.mm; E 220GPa; and the allowable stress is 120 Mpa. Determine the largest weight M which can be supported by the rods. 8c=8s Copper 160 mm Pc Ps Steel 240 mm TIT Pc ..initial level Tinal level Copper 160 mm
6- A circular shaft is composed of a steel core and a brass covering, as shown in the figure. Under the applied torque, what is the maximum shear stress in each material? The composite shaft is attached to a wall at A. B O T= 5 KN•m Steel core r=15mm G=78 GPa bross cylinder ro=20mm (outer diameter) G=39 GPa
Q.1//The bar AD is considered to be absolutely rigid and is horizontal before the load of 200 KN is applied. The connection at A is a pin, and AB is supported on the steel rod BE and the copper rod CF. The length of BE & CF is 250 mm. The cross sectional area of CF is 400 mm, the area of BE is 200 mm. тт. Determine the stress in each of the vertical rods. The weights of all bars are negligible. For copper E=120 GPa, for steel E=200 GPa. 200 KN A• D 1.5 m 500 mm 1500 mm 250 mm steel copper
The compound shaft consists of a solid aluminum segment (1) and a hollow brass segment (2) that are connected at flange B and securely attached to rigid supports at A and C. Aluminum segment (1) has a diameter of 0.90 in., a length of L1 = 55 in., a shear modulus of 3800 ksi, and an allowable shear stress of 5.6 ksi. Brass segment (2) has an outside diameter of 0.75 in., a wall thickness of 0.06 in., a length of L2 = 20 in., a shear modulus of 6400 ksi, and an allowable shear stress of 8.4 ksi. Determine: (a) the allowable torque Tg that can be applied to the compound shaft at flange B (b) the magnitudes of the internal torques in segments (1) and (2). (c) the rotation angle of flange B (relative to support A) that is produced by the allowable torque T.
Load P is applied to joint D and the temperature increases by 50 °F. There are two steel (E = 29*10^6 psi; a = 6.5*10^-6/°F) AD and DC and a bronze (E = 16*10^6 psi; a = 9*10^-6/°F) BD with a length of 50 inches. Each bar is a 0.75 inch diameter. Find the deformation of every rod, the displacement at D, and the stress in each rod.
A shaft composed of segments AC, CD, and DB is fastened to rigid supports and loaded as shown in Fig. P-323. For bronze, G = 35 GPa; aluminum, G = 28 GPa, and for steel, G = 83 GPa. Determine the maximum shearing stress %3D developed in each segment. Tc = 300 N-m C Aluminum Tp = 700 N-m D Steel A Bronze TA TB 25 mm o 25 mm o 50 mm o 2 m 2 m 2.5 m Figure P-323 B.