Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- A circuit with a battery, 2 resistors, a capacitor, and a switch is built as shown in the figure. The battery has voltage V=24.0V, resistor R1= 5.002, resistor R2= 20.02, and capacitor C=150.00µF. At t=0 the switch S is closed and the capacitor C is initially uncharged. 5. R, a. Find the time constant, t, for charging the capacitor. S b. Find the voltage across the capacitor t=4.20x10³s after the switch is closed.arrow_forwardThe switch in the circuit shown below was open for a sufficiently long time and no energy is stored in any of the inductors. It is assumed that the switch is suddenly closed at t=0. Draw the equivalent circuit atI-0*. Then determine the time constant, r, and final value, I Determine the current through the voltage source, i(1), for t2 0 Determine the voltage across the resistor R3, v (1), for 120 1. 2. 3. R 1602 R3 1=0 L 0.52H R, 2402 10492 V's + v1) - L3 100V 1.2H 0.8Harrow_forwardIf in a circuit, E=9v and the current I reaches half its maximum value of 2A at t=0.1s after the switch is closed. What is the time constant of the circuit? What is the emf across the inductor at t=0.1s?arrow_forward
- -In the circuit shown on the right the switch S has been open for a long time. What is the current flow through the inductor (0, 2 to 1, or 1 to 2) ? -In the circuit shown on the right the switch S has been open for a long time. At the instant the switch S is closed, the current flow through the inductor is (0, 1 to 2, or 2 to 1)? -In the circuit shown on the right the switch S has been open for a long time. The current flow through the inductor is (increasing, steady, or decreasing)? -In the circuit shown on the right the switch S has been open for a long time. Immediately after the switch S is closed, the current flow through the inductor is (increasing, steady, or deacreasing)? -In the circuit shown on the right the switch S has been closed for a long time. The current flow through the inductor is (1 to 2, 2 to 1, or 0)? -In the circuit shown on the right the switch S has been closed for a long time. At the instant the switch S is opened, the current flow through the inductor is (1…arrow_forwardHello I need help with part A and part B and part C is there any possible way that you could help me with those three parts and can you label them as wellarrow_forwardSwitch S1 has been closed and S2 has open for a long time until the capacitors are fully charged. At t=0, S1 is opened and S2 is closed. If ɛ=12V, C₁=4mF and C₂-8mF, R₁-3.7kQ and R₂-2.07 kQ; what is the current through the capacitor at t=8 seconds in units of mA? Please express your answer using two decimal places. E R₁ www Answer: C₁- a HH b C₂ S₂ R₂arrow_forward
- The switch in the figure below is open for t < 0 and is then thrown closed at time t = 0. R 2R ww www www (a) Find the current in the inductor. (Use the following as necessary: L, R, t, and for E.) 12- (b) Find the current in the switch as functions of time thereafter. (Use the following as necessary: L, R, t, and & for 8.) switcharrow_forwardAll capacitors were initially discharged.at t = 0, S1 is placed at position 1 and S2 is closed.At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. At t = 25 ms, S1 is kept at position 2 and S2 is opened.after 25 ms, the voltage vT will Question options: increase until it reaches the battery voltage at steady state exponentially decay to zero stay constant be a sine wavearrow_forwardQuestion 2 The switch in Figure 1 has been closed for a long time. It is open at t=0 (the voltage source is disconnected). Let the current i(t) be the output. Derive the differential equation and specify the initial state. 252 www G www.elle 2H i(t) 1F Figure 1 8Varrow_forward
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