Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- Suppose a 250. mL flask is filled with 0.60 mol of NO, and 0.80 mol of O,. This reaction becomes possible: 2NO,(g) = 2NO(g)+O,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. NO, NO O2 initial change equilibrium 미미arrow_forwardNitrogen dioxide is one of the many oxides of nitrogen (often collectively called "NOx") that are of interest to atmospheric chemistry. It can react with itself to form another form of NOx, dinitrogen tetroxide. A chemical engineer studying this reaction fills a 125 L tank with 45. mol of nitrogen dioxide gas. When the mixture has come to equilibrium he determines that it contains 12. mol of nitrogen dioxide gas. The engineer then adds another 11. mol of nitrogen dioxide, and allows the mixture to come to equilibrium again. Calculate the moles of dinitrogen tetroxide after equilibrium is reached the second time. Round your answer to 2 significant digits. | mol x10arrow_forwardSuppose a 500. mL flask is filled with 1.3 mol of O, and 0.10 mol of SO3. This reaction becomes possible: 2s0,(g) +0,(g) – 2s0;(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of 0,. You can leave out the M symbol for molarity. 2. so, 02 so, initial change equilibriumarrow_forward
- Suppose a 250. mL flask is filled with 1.5 mol of CO, 0.30 mol of H,O and 1.3 mol of H,. The following reaction becomes possible: CO(g) +H,0(g)– CO2(g)+H,(g) The equilibrium constant K for this reaction is 1.25 at the temperature of the flask. Calculate the equilibrium molarity of H,O. Round your answer to two decimal places. OMarrow_forwardSuppose a 500. mL flask is filled with 0.70 mol of NO2, 1.7 mol of CO and 0.30 mol of NO. The following reaction becomes possible: NO₂(g) + CO (g) → NO(g) + CO₂(g) The equilibrium constant K for this reaction is 8.94 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. ☐M X Śarrow_forwardNitrogen dioxide is one of the many oxides of nitrogen (often collectively called "Nox") that are of interest to atmospheric chemistry. It can react with itself to form another form of NOx, dinitrogen tetroxide. A chemical engineer studying this reaction fills a 75 L tank with 23. mol of nitrogen dioxide gas. When the mixture has come to equilibrium she determines that it contains 17.9 mol of nitrogen dioxide gas. The engineer then adds another 7.7 mol of nitrogen dioxide, and allows the mixture to come to equilibrium again. Calculate the moles of dinitrogen tetroxide after equilibrium is reached the second time. Round your answer to 2 significant digits.arrow_forward
- Suppose a 250. mL flask is filled with 2.0 mol of Cl₂ and 1.2 mol of HCl. The following reaction becomes possible: H2(g) + Cl2(g) 2HCl (g) The equilibrium constant K for this reaction is 3.70 at the temperature of the flask. Calculate the equilibrium molarity of C12. Round your answer to two decimal places. Шм 000 Ararrow_forwardreaction K Br(aq) + AgNO3(aq) → KNO3(aq) + AgBr(s) CH₂OCH₂ (1) + 30₂(g) → 2CO₂(g) + 3H₂O(g) 2NaClO₂ (s) 2NaCl (s) + 30₂ (g) 2 HBr(aq) + NaOH(aq) → NaBr(aq) + H,O (1) 00000000000000 type of reaction (check all that apply) combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition X 000 000 000 000 precipitation combustion acid-base precipitation combustion acid-base precipitation combustion acid-base precipitation combustion acid-base Śarrow_forwardSuppose a 500. mL flask is filled with 0.20 mol of NO, and 1.3 mol of NO. This reaction becomes possible: 2NO,(g) = 2NO(g)+0,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. NO, NO 0, initial ? change equilibriumarrow_forward
- "Synthesis gas" is a mixture of carbon monoxide and water vapor. At high temperature synthesis gas will form carbon dioxide and hydrogen, and in fact this reaction is one of the ways hydrogen is made industrially. A chemical engineer studying this reaction fills a 75 L tank with 22. mol of carbon monoxide gas and 26. mol of water vapor. When the mixture has come to equilibrium he determines that it contains 13.5 mol of carbon monoxide gas, 17.5 mol of water vapor and 8.5 mol of hydrogen gas. The engineer then adds another 7.0 mol of water, and allows the mixture to come to equilibrium again. Calculate the moles of carbon dioxide after equilibrium is reached the second time. Round your answer to 2 significant digits. || mol x10arrow_forwardSuppose a 250. mL flask is filled with 0.20 mol of N2 and 2.0 mol of NO. The following reaction becomes possible: N2(g) + O2(g) = 2NO(g) The equilibrium constant K for this reaction is 0.693 at the temperature of the flask. Calculate the equilibrium molarity of N2. Round your answer to two decimal places. Шмarrow_forwardSuppose a 250. mL flask is filled with 1.9 mol of O, and 1.5 mol of NO. The following reaction becomes possible: N2 (g) +0,(g) =2NO(g) The equilibrium constant K for this reaction is 8.51 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. OMarrow_forward
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