Suppose a 500. mL flask is filled with 0.40 mol of N, and 0.90 mol of NH3. This reaction becomes possible: N,(g) + 3H,(g) → 2 NH, (g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the M symbol for molarity. N2 H, NH, initial change equilibrium Dlo

Suppose a 500. mL flask is filled with 0.40 mol of N, and 0.90 mol of NH3. This reaction becomes possible: N,(g) + 3H,(g) → 2 NH, (g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the M symbol for molarity. N2 H, NH, initial change equilibrium Dlo

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Suppose a 250. mL flask is filled with 0.90 mol of H, and 0.40 mol of NH,. This reaction becomes possible: N, (g) + 3H,(g) = 2NH, (g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the M symbol for molarity. N, H, NH, initial ? change equilibrium
Suppose a 250. mL flask is filled with 1.5 mol of CO, 0.50 mol of H₂O and 1.2 mol of CO₂. The following reaction becomes possible: CO(g) +H₂O(g) CO₂(g) +H₂(g) The equilibrium constant K for this reaction is 0.503 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. M ܢܢ X E 00 Ar
Write equilibrium expressions for: N₂(g) + 3H₂(g) 2NH₂(g) 3 the reaction as written • the reverse reaction the reaction as written with all coefficients in the equation halved
Suppose a 250. mL flask is filled with 1.1 mol of CO, 0.80 mol of H,O and 0.60 mol of CO,. The following reaction becomes possible: CO(g) +H,0(g) - CO,(g)+H2(g) The equilibrium constant K for this reaction is 5.72 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places. | M
Suppose a 250. mL flask is filled with 1.6 mol of NO and 0.40 mol of NO,. The following reaction becomes possible: NO3 (g) + NO (g) → 2 NO, (g) The equilibrium constant K for this reaction is 0.225 at the temperature of the flask. Calculate the equilibrium molarity of NO3. Round your answer to two decimal places.
Suppose à 250. mL flask is filled with 1.3 mol of CO, 1.8 mol of H,O and 1.6 mol of H,. This reaction becomes possible: co() +H,0(g) =CO,e)+H,(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of H,. You can leave out the M symbol for molarity. CO H,0 Co, H, initial change equilibrium Explanation Check © 2021 McGraw-Hill Education. All Rights Roserved Terms of Use Privacy 1 Ace O Type here to search
Suppose a 500. mL flask is filled with 1.7 mol of Cl₂, 1.1 mol of CHCl3 and 1.3 mol of HCl. The following reaction becomes possible: Cl₂(g) + CHCl3 (g) → HC1(g) +CC14 (g) The equilibrium constant K for this reaction is 9.41 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. 10999
I am confused because I am getting two possible answers one being 10. 6 and the other being 1.38
Suppose a 250. mL flask is filled with 1.5 mol of CO, 0.80 mol of NO and 0.70 mol of CO,. The following reaction becomes possible: 2' NO, (g) +CO(g) - NO(g)+CO,(g) The equilibrium constant K for this reaction is 6.92 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. olo Ar OM ?
Suppose a 500. mL flask is filled with 0.30 mol of SO, and 1.2 mol of SO3. This reaction becomes possible: 2SO, (g) +O,(g) 2SO3 Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. so, SO2 O2 initial change equilibrium
Suppose a 250. mL flask is filled with 1.1 mol of NO3 and 2.0 mol of NO. The following reaction becomes possible: NO3(g) + NO(g) → 2NO,(g) The equilibrium constant K for this reaction is 8.88 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 1.4 mol of N, and 1.3 mol of NO. This reaction becomes possible: N,(2) +0,(2)- -2NO(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the M symbol for molarity. N2 O2 NO initial change equilibrium olo