Steel design Select an economic double equal-leg-angle section for the tension member BH and GC for the truss show Assumptions: ►Use A36 steel. Assume there are two or three bolts in the direction of loading There are two bolts in the transverse direction and not staggered arranged. Use a 7/8-inch diameter bolt. ➤ Given: P =P = 1.2DL + 1.6LL

Steel design Select an economic double equal-leg-angle section for the tension member BH and GC for the truss show Assumptions: ►Use A36 steel. Assume there are two or three bolts in the direction of loading There are two bolts in the transverse direction and not staggered arranged. Use a 7/8-inch diameter bolt. ➤ Given: P =P = 1.2DL + 1.6LL

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.12.2P

See similar textbooks

Similar questions

A 16 mm thick tension member is connected by two 6.25 mm spliced plates as shown. The tension member carries a service loads of dead load of 110 kN and a live load of 100 kN. 40, 80 , 40 , 40, 80 40 1625 mm 16 mm 1625 mm Fy 248 MPa Fu = 400 MPa Diam. of bolts = 16 mm Fnv = 300 MPa O Determine the nominal strength for one bolt due to shear. O Determine the nominal strength for one bolt due to bearing strength of the connection. ® Determine the number of bolts required for the connection.
... A36 (Fy=36ksi; Fu=58ksi) steel is used for the tension member shown. a. Determine the design strength based on the gross area. b. Determine the design strength based on the net area. - PL % ×12 2" 5/8" 2" 4" 12" 4" 2" 4-in.-diameter bolts Cross Sectional area of PL3/8x6 a) Blank 1 b) Blank 2 Blank 1 Add your answer Blank 2 Add your answer
A rigid bar AC is supported pinned supported at A and bar DB at B. See typical bolt connection detail. A concentrated weight, denoted as W is attached at the end of the rigid bar. L1 = 2.6 m L2 = 2.1 m H= 1.2 m W= 14 KN What is the required diameter of the bolt (in mm) at connection B given the allowable shearing stress to be 40 MPa ? Consider single shear. L1 L2 A B C H D इस W CONNECTION AT B
A double-angle tension member, 2L 3 x 2 x 4 LLBB, of A36 steel is subjected to a dead load of 12 kips and a live load of 36 kips. It is connected to a gusset plate with one-line of 3/4-inch-diameter bolts through the long legs. Does this member have enough strength? Assume that A₂ = 0.85An. Ae Use LRFD. Use ASD. 1 2 IL Section CIVIL ENGINEERING STEEL DECIGN
A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H G P P D B F C A E
A 10mm x 150 mm plate of A36 steel (Fy = 248 MPa & Fu = 400 MPa) is used as a tension member. It is connected using 20 mm Ø bolts. U=1.0 a. Determine the tensile capacity based on yielding (ASD & LRFD) b. Determine the tensile capacity based on rupture (ASD & LRFD) c. Determine the tensile capacity based on block shear strength (ASD & LRFD) 75mm 37.5 75 75 75 87.5
A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H FO E. • D A В
A PL 38 X 6 tension member is welded to a gusset plate as shown. The steel is A36 (Fy = 36ksi, Fu = 58ksi). a. The design strength, Pu based on gross area b. The design strength, Pu based on effective area PL % x6 3/8" 6" Cross Sectional area of PL3/8x6 a) Blank 1 b) Blank 2
The tension member is a PL 1⁄2 × 6. It is connected to a 3⁄8-inch-thick gusset plate with 7⁄8-inch-diameter bolts. Both components are of A242 steel. Note: A242 Fu = 70ksi dh = db + 1/16’’ Use: Consider deformation at the bolt hole Compute the nominal strength in bearing on Gusset plate only (since this will govern, it has smaller thickness than the main member PL ½ x 6)
Plate A, PL 16mm x 375mm, is connected to another plate B with 10- 22 mm o bolts as shown. The steel is A36 steel with Fy= 250 MPa and F,= 400 MPa. Assume that plate B has adequate strength. Use ASD. Plate B 375a 75 m 2 75mm Plate A 75 mm 75mm 150 50150 Compute the nominal strength based on yielding in KN.O Determine the allowable tensile strength of Plate A in KN.O Compute the allowable tensile strength at section a-1-2-2-4-c in KN.0
Bottom chord of truss is composed of two angle bars each having a dimension of 185 mm x 146 mm x 8.7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 44 mm and 59mm pitch. Use A36 steel Fy 248 MPa Fu = 400 MPa %3D spacing of bolt = 68.9 mm %3D 9 5mm thick gunset plate edge dist Compute the capacity of the bottom chord based on block shear strength, in KN. uad
The tension member is a PL 1⁄2 × 6. It is connected to a 3⁄8-inch-thick gusset plate with 7⁄8-inch-diameter bolts. Both components are of A242 steel. Note: A242 Fu = 70ksi dh = db + 1/16’’ Use: Consider deformation at the bolt hole