Design the reinforcements of the given T beam below. bf=900mm bw=420mm tf=120mm d=550mm d'=80mm fc'=34MPa fy=415MPa USE NSCP 2015 A.Mu = 1300kN-m, As = mm2 B.Mu = 1800kN-m, As = mm2, As' = mm2
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- أ.د. رمضان المبروك A PL170mm x 10mm tension member is welded to a gusset plate as shown in Figure below. The steel is A36. Assume that Ae = Ag and compute the following. %3D fy = 250 MPa & f, = 400 MPa %3D %3D PL 170mmx10mm a. The design strength for LRFD. . The allowable strength for ASD. roblem (4):Design the reinforcements of the given T beam below. bf=800mm bw=450mm tf=120mm d=600mm d'=80mm fc'=35MPa fy=350MPa USE NSCP 2015 A.Mu = 1300kN-m, As = B.Mu = 1600kN-m, As = mm2 _mm2, As' = mm2A For the truss shown, find veyticat deflection bylunit lead Methed. EA 15 _atfd) Ioku for all members increase in temp is (50€) in (ad) short in (ad)is (3 Emfr
- W3D 25 Y= 155 %31 1oow= 2500 KN 27=310mm X= 475 Z= 60 %3D 102=600mmsted ingid 250MM B k steel bar bolt AUR rigid bar 12 mm thick 8 mm Brass 350mm Jointd 16 mene thick 350mm JointB 250 mm Xg = 20x10% Eg = 90 G Pa -6 A, = 12x10/0 Es = 200 G Pa thickness> 16 mm 8 mm bolt %3D 12 mmi thick shear strength f bolf bearing streng th of holt= 100 la 50 MPa %3D Assume no failure will take place in steel or brass. Temperature chauge brass steel on Temperature change on Determine thai can be applied to system - the maxPSD323- Principles of Steel Design 4. The tee section is made up of a 30mmx150mm flange and a 30mmx160mm web. Determine the properties of a section(MOI, section modulus, radius of gyration) 15d mm 30 mm A, 6 Yu d, N.A. di 30 tnm 160 mm
- A built-up section shown, 30 feet long, is fixed at both ends and braced in the weak direction at the midheight. A992 steel is used. Determine the following: 11. Ix 12. Ky 13. effective slenderness ratio 14. Fe 15. LRFD design strength 16. ASD allowable strength 18 4 W10 × 49 A 14.4 in² bf 10 in d. 10 in tw 0.340 in tf 0.560 in Ix= 272 in¹ Iy=93 4in¹ W10×54 A 15-3 in² bf 10 in d = 10 lin tw0-370 in tf 0.615 in Ix= 303 in 4 Ty = 103 in 1A76 x 76 x6 mm angular section shown is welded to an 8 mm thick gusset plate. The length L1 is 65 mm, L2 is 125 mm, and the cross sectional area of the angle is 929 sq.mm. Fy-248MPA and Fu -400MPA. Gusset Plate Alowable Sresse Alowable tensle stress igross ara)0.00 Alowable tereile stres net area)0SOF. Allowable shear stress (net ares)0.30F. Determine the value of P based on net area using a strength reduction coefficient of 85% O 138.24 KN O 140.14 kN O 157.93 kN O 304.00 N Next500 mm 62.5 mm 375 mm 62.5 mm P. Determine the total required number of 20mm bars to be used in two end faces only for the 300mm x 500mm rectangular column shown to support the following loads: Pu = 800 kN Mu = 120 kN-m Use f'c = 20.7 MPa and fy = 413.7 MPa Use 1 ksi = 6.893 MPa %3D 300 mm O O O O
- Determine the design moment capacity of the beam with given properties below. bf = 550mm bw 350mm tf = 100mm %3D d = 370mm %3D d' = 100mm %3D fc' = 34.5 MPa fy = 400 MPa %3D As = 6-32mm bars a USE NSCP 2001, Mu = kN-m b. USE NSCP 2015, Mu = kN-m7 7a 7b 7c Alaterally supported beam was designed for flexure. The beam is safe for shear & deflection. The most economical section is structural tubing however the said section is not readily available at the time of the construction. If you are the engineer in charge of the construction what alternative section will be the best replacement? Why? The section is 8" x 8" x 7.94 mm thick: Use Fy=248 MPa: E=200,000 MPa AISC wall thickness Ix 106 S x 103 Jx 103 mm4 mm3 mm4 rx =ry Area Ag (mm2) mm Designation Weight/m 8x8 7.94 47.36 6,039 79.25 37.84 371.99 60.35 expla'n briefly your cho'ce. (transform your comparative analys's 'nto a narative form to support your cho'ce) 8x8 14.29 80.61 10,258 76.2 59.52 585.02 99.06 8x8 72.7 9,290 76.96 54.53 539.13 90.32 8x8 9.53 56.09 7,161 78.48 44.12 432.62 70.76 mm 12.7 Zx 103 mm3 437.53 714.48 650.57 512.9216) what is the tensile yielding capacity of flange plate of the flange connection in kips? (2 decimal places) A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi