State the expected ratio of ebony to non-ebony flies in the F2 generation. State the expected ratio of stubble to non-stubbly flies in the F2 generation.
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Table 1:
F1 ebony flies - 0
F1 non-ebony flies - 560
F1 stubble flies - 560
F1 non-stubble flies - 0
The researcher collects and crosses male and female flies from the F1 generation. In the resulting offspring, F2, there are both stubble and ebony flies.
State the expected ratio of ebony to non-ebony flies in the F2 generation.
State the expected ratio of stubble to non-stubbly flies in the F2 generation.
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- Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?What is the map unit distance between the two genes? She obtains the following flies from this testcross. vg+ bwd+ 270 vg bwd 264 vg bwd+ 57 vg+ bwd 59Consider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PCR was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PCR products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?
- Below are the results from a 3 gene testcross between an XxYyZz plant and an xxyyzz plant: Testcross outcome: XYZ 365 xyz 367 xYz 110 XyZ 105 XYZ 3 Xyz 4 XYZ 25 xyZ 21 1. Determine the order of these genes on the chromosome. Indicate them on the diagram below. 2. Calculate the map distances between the genes (give you answer as map units). Indicate these distances on the diagram above. 3. Determine the coefficient of coincidence. 4. Determine the interference among these genes.The picture shows a gel of PCR products for the loci SRY, AMELX/Y and ZFX/Y, for three controls and five test human individuals (1-5). Below the gel is the phenotypic sex of each individual, their fertility status, and the number of Barr bodies seen in the nucleus of a somatic cell in each case. The diagram to the right shows the positions of the tested loci on the human sex chromosomes, and also the positions of the PRKX and PRKYgenes. Which sample carries a derived X chromosome with a translocation due to ectopic crossover between the loci PRKX and PRKY: 46,X,derX,t(X,Y); ? 1 2 3 4 5The following table summarises the results of the 2022-2023 Drosophila three-point cross involving the loci white eyes (w), miniature wings (m) and singed bristles (sn). The data is also available in the Excel file 'Drosophila Counts 2022-2023'. We strongly recommend working in Excel during this exercise.Phenotype Count+ + + 584w m sn 324w + + 227+ m sn 150+ m + 134w + sn 196 + + sn 134 w m + 92The aim of today's tutorial is to use the above data to establish the genetic map for these three loci. We have been told that all three loci are on the X chromosome; however, as scientists, we shouldn't simply take someone else's word for it - we need to test whether our data does, in fact, indicate linkage.As a first step, we will therefore conduct a chi-square test in order to test our data against the null hypothesis of independent assortment (i.e., "no…
- Cross Cross A Cross A Cross B Cross B Phenotype F1 generation F2 generation F1 generation F2 generation Male red eyes 132 150 0 99 Female red eyes 135 295 110 101 Male white eyes 0 147 105 93 Female white eyes 0 0 0 95 Using “+” to indicate the wildtype red-eyed allele and “w” to indicate the mutant white-eyed allele, state the genotypes of the following: Wildtype red-eyed and white-eyed parental flies from cross A and cross B. Males and females from the F1 generation flies from cross A and cross B Males and females, F2 generation flies from cross A and cross B.Shown below are photomicrographs of Rhoeo tradescantia cells undergoing meiosis. Answer the following question for each of the photomicrographs: Identify the cytogenetic abnormality observed (ex. ring, chain, laggard, bridge). Identify the meiotic stage in which these aberrations are observed (as shown in the photomicrograph). Explain how these aberrations are formed and relate to the possible causal mutation(s). Will this result to sterile and/or fertile gametes? Explain.I have a vial of F2 offspring resulting from a two-generation cross between true-breeding wildtype females and true-breeding pink-bodied males. I scored F2 phenotypes for a total of 120 flies and obtain the following data: Based on the above observed data in the chart, determine the expected number of flies for the following three scenarios provided in a-c below. 1) The mutant allele is recessive and is located on an autosome:
- PURPLE VESTIGIAL DIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (put/put.vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (put/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (put/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Wild-type Purple, vestigial Vestigial Purple Genotype Tester Gamete Dihybrid Gamete Number 437 417 77 59 Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete…A complementation analysis was performed using Drosophila which normally have black wings. Six mutants for clear wings were discovered. The mutants were bred in a complementation test to produce the following: Mutant 2 4 # 1 1 1 1 2 1 1 1 1 1 1 4 1 1 Where a "0" (zero) means clear wing offspring and a "1" (one) means wildtype (black wing offspring). How many genes can you identify that affect the production of wing colour in Drosophila? O a. 3 O b.4 О с. 5 O d. 6 O e. none of the above 3. 5The data set attached presents the results of a testcross using female flies heterozygous for three traits and male flies, which are homozygous recessive. For simplicity, mutant alleles are shown with letters a, b, and c and wildtype alleles are indicated by a “+” symbol. For this part of the report do the following in order: a) Determine the gene order (which gene is in the middle?)d) Construct a genetic map for the three genes, including the map distances between them. Clearly indicate the logic you followed and show all your calculations. Include the full distance calculations for the two most distanced genes (do not just add the other 2 distances). Ensure the work is neat and clear and does not contain spelling or grammatical errors so that it is understandable. Make sure to double check the solution provided.
