SNP A SNP B Results of ASO (antisense oligonucleotide) genotyping for two SNP markers are shown here for individual III-1 in the pedigree provided for Question 8. Orange indicates the presence of a hybridization signal and white indicates no hybridization. Which of these markers could be the one informing the SNP genotype designation "1,2" for individual III-1? SNP A Could be either SNP B
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- 3.27 Complementation tests of the recessive mutant g genes a through f produced the data in the accom- panying matrix. The circles represent missing data. beaim Assuming that all of the missing mutant combina- motions would yield data consistent with the entries ithat are known, complete the table by filling each oneel circle with a + or – as needed. - rt yd bat 21 igi a rıb a O + b c d e fi 612 nobsdi b liw insiqans bosale yns mon las 29 ni YOu C ono e 66 BA AA f AAstion 6 of 18 Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She calls this mutation quiver, qu, and determines that it is due to an autosomal recessive gene. She wants to determine whether the gene encoding quiver is linked to the recessive gene for vestigial wings, vg. She crosses a fly homozygous for quiver and vestigial traits with a fly homozygous for the wild-type traits, and then uses the resulting F, females in a testcross. She obtains the flies from this testcross. Phenotype Number of flies vg* qu+ 230 vg qu 224 vg qut vg* qu 97 99 Test the hypothesis that the genes quiver and vestigial assort independently by calculating the chi-squared, X², for this hypothesis. Provide the X2 to one decimal place. X2 = Does the X value support the hypothesis that the quiver and vestigial genes assort independently? Why or why not? the partial table of critical values for X2 calculations to test this hypothesis.Fill the blank A DNA _________ contains allele-specific oligonucleotides(ASOs) for millions of SNP loci. Under the properconditions, a probe made of fluorescently-labeledgenomic DNA fragments binds only to complementaryASOs, allowing these loci to be genotyped.
- 5.64 x 10^6 base pairs Short questionsPhenotype chr1.1 chr2.8 chr3.12 chr4.12 chr4.55 chr7.88 chr9.55 chr10.1 chrX.1 chrX.5 Purple AA AT Purple AA AT F F GG GC 80 CC CC TT TT TT CT 80 CC CC AT TT TT CT 8 CC CC AT AT GG CT GC TT CC AT AT GT 10 CT Yellow AA AT TT GC Purple and AA TT Yellow F Purple AA AT AA GG TT GC AT TT TT CT Purple AA AT AA GG TT GC AT TT TT CT Purple AA AT AA Purple AA AT AA 80 CC TT GG AT TT TT TT 646 GG CC GG AT TT TT TT Purple and AA TT AT CC 80 Yellow 80 CC GG AT AT GT TT Purple AA AT AT CC CC GC AT F TT TT TT E Purple AA AT AT CC TT GC AT TT TT CC Purple AA AT E 00 CC TT GG AT TT TT CC Yellow AA AT AT GC TT 00 CC AT AT GG CC 80 TT E AT AT GC CC CC AT AT GG TT Yellow AA AT AT GG CC CC AT AT GG Yellow AA ধ 80 CC CC AT AT GT TT GG TT GG AT AT GG TT Purple and AA AA AT GG Yellow Yellow AA AA F 80 CC GG AT TT TT CC 80 GC CC GG AT AT GT CC Purple AA AA AT GC Purple and AT AA Yellow Purple AA AA F F GG 80 CC GG AA TT GT CCName Sofia Falcione P Pedigree Analysis Practice - for each pedigree, write the genotypes of the individuals The disorder shown on the pedigree is Maple Syrup Urine Disease (MSUD) which is a metabolic disorder that affects the body's ability to process certain proteins. It was named after a distinctive odor of a baby's urine. 1. What is the inheritance pattern of this gene? a) autosomal dominant b) autosomal recessive c) X-linked recessive 2. Provide at least one piece of evidence for your claim. This pedigree shows the inheritance Leber congenital amaurosis (LCA) which is a type of hereditary blindness. Individuals with this disease lose their vision during childhood. 3. What is the inheritance pattern shown? 4. Highlight one individual whose genotype is unknown. What additional information would you need to determine his/her genotype? Marfan syndrome affects the connective tissue and causes individuals to have long, thin, arms, legs, fingers and toes. 5. What is the inheritance…
- GsnKivd010j2gIRWLIZOMZZ-VibKYvBbo61ylATAQ/viewform RECOMBINATION". For numbers 7-35, reler to the given data below. Glven the following testcross data for com In whlch the genes for fine stripe (f), bronze gleurone (bz) and knotted leaf (Kn) are involved: + = wild type f fine stripe +=wild type bz = bronze gleurone +=wild type Kn knotted leaf %3D Genotype Ko f Number 451 Ko 134 97 436 bz bz bz Ko 18 119 f 24 Kn f bz 86 Total: Your answer 7-8. What would be the recombination frequency or the frequency of the recombinant type between +/Kn and +/f genes? Oa. 16% O b. 16 map units + + + + +In an in situ hybridization experiment, a certain clonebound to only the X chromosome in a boy with no diseasesymptoms. However, in a boy with Duchenne musculardystrophy (X-linked recessive disease), it bound to theX chromosome and to an autosome. Explain. Could thisclone be useful in isolating the gene for Duchenne muscular dystrophy?F1 hybrids between two species of cotton, Gossypium barbadenseand Gossypium hirsutum, are very vigorous plants. However, F1crosses produce many seeds that do not germinate and a high percentageof very weak F2 offspring. Suggest two reasons for theseobservations.
- 3.11 The accompanying gel diagram shows the banding patterns observed among the progeny of a crossS between double heterozygous genotypes shown at the left (P1 and P2). On the right are shown the pat- emoterns of bands observed among the progeny. The P60r bands are numbered 1-4.Karyogram and Identification of Chromosomal Aberrations List down five human chromosomal aberrations. Give the corresponding karyotype for each type then briefly describe the traits of affected individuals.On Neurospora chromosome 4, the leu3 gene is just to theleft of the centromere and always segregates at the firstdivision, whereas the cys2 gene is to the right of the centromere and shows a second-division segregation frequency of 16 percent. In a cross between a leu3 strain anda cys2 strain, calculate the predicted frequencies of thefollowing seven classes of linear tetrads where l = leu3 andc = cys2. (Ignore double and other multiple crossovers.)