A man with Huntington disease (he is heterozygous HD HD) and a normal woman have two children. a. What is the probability that only the second child has the disease? b. What is the probability that only one of the children has the disease? c. What is the probability that none of the children has the disease? d. Answer (a) through (c) assuming that the couple had 10 children. e. What is the probability that 4 out of the 10 children in the family in (d) have the disease?

Biology (MindTap Course List)
11th Edition
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Chapter11: The Basic Principles Of Heredity
Section: Chapter Questions
Problem 5TYU: Assume that the ratio of females to males is 1:1. A couple already has two daughters and no sons. If...
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A man with Huntington disease (he is heterozygous HD HD
normal woman have two children.
a.
What is the probability that only the second child has the disease?
b. What is the probability that only one of the children has the disease?
c. What is the probability that none of the children has the disease?
d. Answer (a) through (c) assuming that the couple had 10 children.
and a
e. What is the probability that 4 out of the 10 children in the family in (d) have the
disease?
Transcribed Image Text:A man with Huntington disease (he is heterozygous HD HD normal woman have two children. a. What is the probability that only the second child has the disease? b. What is the probability that only one of the children has the disease? c. What is the probability that none of the children has the disease? d. Answer (a) through (c) assuming that the couple had 10 children. and a e. What is the probability that 4 out of the 10 children in the family in (d) have the disease?
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