slit of width 0.46 mm is illuminated with light of wavelength 534 nm, and a screen is placed 114 cm in front of the slit. Find the widths of the first and second maxima on each side of the central maximum. w1 = mm (1st maxima) w2 = mm (2nd maxima)

In an interference experiment using a monochromatic source emitting light of wavelength 1, the fringes are produced by two long, narrow slits separated by a distance d. The fringes are formed on a screen which is situated at a distance D >> d.Write down an expression for the fringe width w. Please use "*" for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. Use "lambda" (without the quotes) for 1 in the equation box. For example, use d*lambda for d2. Please use the "Display response" button to check you entered the answer you expect. w=

You measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cm

A slit of width 0.45 mm is illuminated with light of wavelength 544 nm, and a screen is placed 110 cm in front of the slit. Find the widths of the first and second maxima on each side of the central maximum. w1 =  mm (1st maxima) w2 =  mm (2nd maxima

Light with wavelength 2 passes through a narrow slit of width w and is seen on a screen which is located at a distance D in front of the slit. The first minimum of the diffraction pattern is at distance d from the middle of the central maximum. Calculate the wavelength of light if D=2.4 m, d =1 mm and w = VAD.Give your answer in nanometers. Answer: Choose...