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Transcribed Image Text:Two coherent radio point sources separated by 2.0m are radiating in phase with a wavelength
2=0.50m. A detector moved in a circular path around the two sources in a plane containing them
will show how many maxima?
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- Monochromatic, in phase light of wavelength > 752nm is incident on a piece of metal with either one or two slits on it - it is difficult to see to determine which. The diffraction pattern is observed on a viewing screen that is located 55cm away from the metal plate. The first two minima are measured to be 2.3cm and 7.0cm away from the central maxima. What is the brightness of the light at a distance of 6.3cm from the central maxima, relative to the brightness of the central maxima? x10-3 Note: Brightness is proportional to the SQUARE of the amplitude. For double slit, this means I = I (cos(d sin ) º)) ². 2 I = I₂ sin (5) xd sin 0 . For single slit, this means In both of these, I, is the maximum brightness, and d is the characteristic spacing of the slit(s).arrow_forwardWhich of these is the theoretical maximum number of bright fringes visible in the diffraction pattern when green (I = 500 nm) light shines through double slits separated by 2.1 * 10^-6m?arrow_forwardA particular person's pupil is 4.5 mm in diameter, and the person's normal‑sighted eye is most sensitive at a wavelength of 552 nm. What is angular resolution ?R of the person's eye, in radians?arrow_forward
- To make a hologram using an Argon laser (1 = 0.488 µm), the maximum angle between objective and reference beams is 0max resolution (or spatial frequency) of the holographic recording film (fo – lines per mm)? 40°. What is the requirement on the minimum 0.633 um). Assume that z, When the hologram is reconstructed using a HeNe laser (A 10cm, z, = 2z,, Zp transversal and axial magnification (M; and Ma). = 00, please compute virtual and real image locations (Fz;), thearrow_forwardThe full width at half-maximum (FWHM) of a central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (See figure (b).) (a) Does the intensity drop to one-half the maximum value when sin²α = a²/2? (b) Is a = 1.39 rad (about 80°) a solution to the transcendental equation of (a)? (c) Is the FWHM AÐ = 2sin¹(0.442 A/a), where a is the slit width? Calculate the FWHM of the central maximum for slit width (d) 1.17 A, (e) 5.03 A, and (f) 11.7 A. 20 20 Relative intensity 15 10 0.8 0.6 a=2 0.4 0.2 5 05 8 (degrees) (a) 10 15 20 20 Relative intensity 1.0 0.8 0.6 -A0- 0.4 0.2 a= 52 20 15 10 5 0 5 10 15 20 (degrees) (b)arrow_forwardProblem 17: Suppose a 1.8 μm wide slit produces its first minimum for 410 nm violet light.Randomized Variablesλv = 410 nmλr = 750 nmw = 1.8 μm Part (a) Calculate the angle at which this occurs for violet light in degrees.Numeric : A numeric value is expected and not an expression.θv = __________________________________________Part (b) Where is the first minimum (in degrees) for 750 nm red light?Numeric : A numeric value is expected and not an expression.θr = __________________________________________arrow_forward
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